The typical case is IFS= read
.
The subject is very well explained in this thread:
why is setting a variable before a command legal in bash?
In order to have a complete picture, I'd be very grateful if you guys could explain why the following script doesn't work as (I) expected.
my_script
:
#!/bin/bash
echo "$var1"
echo -n "$IFS" | xxd -p
echo "$var2"
exit 0
calling my_script
:
var1=foo IFS= var2=bar my_script
output:
foo
20090a
bar
As you can see IFS
is unchanged, still set as default.
How does read
get the custom IFS
when called as IFS= read
?
Thank you in advance
-
See also When can I use a temporary IFS for field splitting? (but, as Thomas Dickey's answer explains, you aren't getting that far).Gilles 'SO- stop being evil'– Gilles 'SO- stop being evil'2016年02月21日 21:00:07 +00:00Commented Feb 21, 2016 at 21:00
1 Answer 1
The example does not set IFS
within the script, because bash disallows importing IFS
from the environment, according to a comment in variables.c
:
/* Don't allow IFS to be imported from the environment. */
temp_var = bind_variable ("IFS", " \t\n", 0);
setifs (temp_var);
Built-in commands and non-script uses get the assignment to IFS
, of course, but keep in mind that IFS
only applies to word-splitting:
The shell treats each character of
$IFS
as a delimiter, and splits the results of the other expansions into words using these characters as field terminators. IfIFS
is unset, or its value is exactly<space><tab><newline>
, the default, then sequences of<space>
,<tab>
, and<newline>
at the beginning and end of the results of the previous expansions are ignored, and any sequence ofIFS
characters not at the beginning or end serves to delimit words. IfIFS
has a value other than the default, then sequences of the whitespace characters space and tab are ignored at the beginning and end of the word, as long as the whitespace character is in the value ofIFS
(anIFS
whitespace character). Any character inIFS
that is not IFS whitespace, along with any adjacentIFS
whitespace characters, delimits a field. A sequence ofIFS
whitespace characters is also treated as a delimiter. If the value ofIFS
is null, no word splitting occurs.