Bash- modify code for a custom output statement

Question

The script will read the contents of a user-input file and count the number of employees with a specific job. Ex file line:

Sophia Lewis, 542467, Accountant 

The script I have so far is:

if [ -s 1ドル ]
then
cat 1ドル | tr -s ' ' | cut -d' ' -f4- | sort | uniq -c
else
 echo "ERROR: file '1ドル' does not exist."
fi

Output:

4 Sales 
2 Accountant 
1 CEO 

But I want the output to appear as:

There are 4 ‘Sales’ employees. 
There are 2 ‘Accountant’ employees. 
There is 1 ‘CEO’ employee. 
There are a total of 7 employees in the company

Should I take out the cat and put in echo statements so I can customize each line? And is there a way for it to know if it should be "is/are" x employees?

• terdon: Yes, you will need to rewrite it and no, the only way for it to know is for you to code it.

Answer 1

If your shell is bash version 4:

declare -i total=0
declare -A type
if [ -s "1ドル" ]; then
 while IFS=, read name id job; do
 [[ $job =~ ^[[:space:]]*(.+)[[:space:]]*$ ]] &&
 (( type["${BASH_REMATCH[1]}"]++, total++ ))
 done < "1ドル"
 for job in "${!type[@]}"; do
 printf "There are %d '%s' employees.\n" ${type["$job"]} "$job"
 done
 echo "There are a total of $total employees in the company"
else
 echo "ERROR: file '1ドル' does not exist or has zero size."
fi

Or use awk:

awk -F' *, *' '
 { type[3ドル]++; total++ } 
 END {
 for (job in type) 
 printf "There are %d '\''%s'\'' employees.\n", type[job], job
 print "There are a total of", total, "employees in the company"
 }
' "1ドル"