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I am an amateur programmer.
(削除) I hate programming. (削除ここまで)smjshxjd
I do math for fun.
99.9̅% of all people can't solve this question:
If $\zeta(s)=\sum_{n=1}^\infty \frac1{n^s}$ for $\Re(s)>1$ and its analytic continuation elsewhere, do all the non-even zeros of $\zeta$ have real part $\frac{1}{2}$?
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