PHP array to JavaScript array via Ajax request

Question

I want the result of this Ajax request to fill the JavaScript hintArray. That is, I want hintArray to contain the same values as $row. Can this be done in a simple way? How should the php file output be made? Is hintArray = JSON.parse(this); correct?

Many thanks

JavaScript

var hintArray = new Array();
postAjaxRequestFunktion(minFunktion, 'getHint.php', 'id =1')
function minFunktion()
{
 hintArray = JSON.parse(this); 
}
function postAjaxRequestFunktion(minFunk,minUrl, mittArg)
{
 var contenttype = 'application/x-www-form-urlencoded'
 var minRequest = new skapaAjaxObjekt(minFunk)
 if (!minRequest) return false
 minRequest.open('POST', minUrl, true)
 minRequest.setRequestHeader('Content-type', contenttype)
 minRequest.setRequestHeader('Content-length', mittArg.length)
 minRequest.setRequestHeader('Connection', 'close')
 minRequest.send(mittArg)
 return true
}
function skapaAjaxObjekt(minFunk)
{
 try { var minRequest = new XMLHttpRequest() }
 catch(e1) { try { minRequest = new ActiveXObject("Msxml2.XMLHTTP") }
 catch(e2) { try { minRequest = new ActiveXObject("Microsoft.XMLHTTP") }
 catch(e3) { minRequest = false }}}
 if (minRequest) minRequest.onreadystatechange = function()
 {
 if (this.readyState == 4 && this.status == 200 &&
 this.responseText != null)
 minFunk.call(this.responseText)
 }
 return minRequest
} 

getHint.php

$result = mysql_query("SELECT hint01,hint02 FROM main WHERE id = '00000001'");
if (!$result) {
 echo 'Could not run query: ' . mysql_error();
 exit;
}
$row = mysql_fetch_row($result);

Answer 1

you should encode your php array with

json_encode($your_array);

and decode it in javascript with eval

your_js_array = eval('(' + yourJSONtext + ')');

• Fred: I added this to the .php file: echo json_encode($row); And this to JS: function minFunktion() { hintArray = eval('(' + this + ')'); } But it doesn't work. The JS array is empty. What am I doing wrong? If I instead add this to JS: function minFunktion() { document.getElementById('hint').innerHTML = this } This is written in the hint element: ["hintText1"," hintText2"]
• Packet Tracer: has "this" a value? use console.info(this); or console.info(this.responseText); .Are you receiving something??
• Fred: I did a mistake but rectified it and now your solution works perfectly. Many thanks for showing me this simple way to solve it!