Invoking plugin methods

Question

How do I invoke a private method from a public one and vice versa if I follow the plugin authoring guide?

I usually declare the private methods within the init method like:

var methods = {
 init: function(options) {
 var settings = $.extend({
 }, options);
 return this.each(function() {
 var $this = $(this);
 var data = $this.data('griffin-editor');
 this.trimSpaceInSelection = function () {
 //how do I call a public method here?
 //to get the this context correct.
 }
 if (typeof data !== 'undefined') {
 return this;
 }
 //the rest of the code.

It might be the incorrect thing to do?

• elclanrs: Why is it any different with the plugin guide? This might help stackoverflow.com/questions/6420825/…
• elclanrs: I see...I'm finding out things as I go. These might help, 1, 2, 3

Answer 1

If by 'this context correct' you mean that you want call some public method with this set to value which this has inside trimSpaceInSelection then you can do it like this:

....
this.trimSpaceInSelection = function () {
 methods.somePublicMethod.apply(this, arguments); // this will pass all arguments passed to trimSpaceInSelection to somePublicMethod
}
....

And if you want set this inside public method to current jQuery collection then:

....
this.trimSpaceInSelection = function () {
 methods.somePublicMethod.apply($this, arguments); // this will pass all arguments passed to trimSpaceInSelection to somePublicMethod
}
....

• jgauffin: Works like a charm. thanks. I do this to create the args array: var args = [];args[0] = actionName; are there a nicer way to do it?
• jgauffin: I just declare that before calling methods.somePublicMethod.apply($this, arguments); in your example.
• Mateusz W: you can do in two ways: methods.somePublicMethod.call($this, firstArg, secondArg, thirdArg);, or methods.somePublicMethod.apply($this, [firstArg, secondArg, thirdArg]); This can help: stackoverflow.com/questions/1986896/…