parsing in python

Question

I have following string

adId:4028cb901dd9720a011e1160afbc01a3;siteId:8a8ee4f720e6beb70120e6d8e08b0002;userId:5082a05c-015e-4266-9874-5dc6262da3e0

I need only the value of adId,siteId and userId. means

4028cb901dd9720a011e1160afbc01a3

8a8ee4f720e6beb70120e6d8e08b0002

5082a05c-015e-4266-9874-5dc6262da3e0

all the 3 in different variable or in a array so that i can use all three

Answer 1

You can split them to a dictionary if you don't need any fancy parsing:

In [2]: dict(kvpair.split(':') for kvpair in s.split(';'))
Out[2]:
{'adId': '4028cb901dd9720a011e1160afbc01a3',
 'siteId': '8a8ee4f720e6beb70120e6d8e08b0002',
 'userId': '5082a05c-015e-4266-9874-5dc6262da3e0'}

• Ants Aasma: It's a copy paste from ipython interactive shell.

Answer 2

You could do something like this:

input='adId:4028cb901dd9720a011e1160afbc01a3;siteId:8a8ee4f720e6beb70120e6d8e08b0002;userId:5082a05c-015e-4266-9874-5dc6262da3e0'
result={}
for pair in input.split(';'):
 (key,value) = pair.split(':')
 result[key] = value
print result['adId']
print result['siteId']
print result['userId']

Answer 3

matches = re.findall("([a-z0-9A-Z_]+):([a-zA-Z0-9\-]+);", buf)
for m in matches:
 #m[1] is adid and things
 #m[2] is the long string.

You can also limit the lengths using {32} like

([a-zA-Z0-9]+){32};

Regular expressions allow you to validate the string and split it into component parts.

Answer 4

There is an awesome method called split() for python that will work nicely for you. I would suggest using it twice, once for ';' then again for each one of those using ':'.