How check a string value inside a list on a if statement?

Question

I have the following code:

s = ['01','06','11','16','21','26','31','36','41','46','51','56']
while True:
 for a in s:
 if time.strftime('%S') == a: 
 print 'YES'
 else:
 print time.strftime('%S')
 time.sleep(1)
 print a

And it doesn't work.

Any ideas how to make it work?
In case, everytime the %S gets some of the value in s, it prints the 'YES'.

• Rik Poggi: Why os not working? There is an error? And what exactly should your program do?
• Joel Cornett: I agree with Rik. You should make it a habit to include the traceback in your question.

Answer 1

You need to call sleep on every loop and look for the current seconds in your list of matches:

>>> import time
>>>
>>> matches = ['01','06','11','16','21','26','31','36','41','46','51','56']
>>>
>>> while True:
... seconds = time.strftime('%S')
... if seconds in matches:
... print('YES')
... else:
... print(seconds)
... time.sleep(1)
...
07
08
09
10
YES
12
13
14
15
YES
17
18
19