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print("Hi im a PC and my name is Micro, What's your name?")
name = raw_input("")
print("Hi " + name + " how are you, are you good?")
answer = (raw_input(""))
if answer == "yes":
 print("That's good to hear!")
elif answer == "no":
 print("Oh well")
while answer != ("yes","no")
 print("Sorry, you didnt answer the question properly, Please answer with a yes or no.")
print"I'm going to sleep for 5 seconds and then i'll be back."
import time
time.sleep(5)
print"I'm back!"

need to create a loop for the yes or no bit, anyone know how? thanks for any help!

Will Vousden
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asked Jan 7, 2012 at 9:23
1
  • 1
    It's okey to be new at something. But may I suggest you look thru these serie of videos: youtube.com/watch?v=tKTZoB2Vjuk&ob=av3e or something similar? That will take you a few hours but it will be totally worth it. You will get some basic understanding of how things work :) Commented Jan 7, 2012 at 9:44

2 Answers 2

1

Use while True: and when you want to stop the loop use break.

This would be your code than:

...
while True:
 answer = (raw_input(""))
 if answer == "yes":
 print("That's good to hear!")
 break
 elif answer == "no": 
 print("Oh well")
 break
 else:
 print("Sorry, you didnt answer the question properly, Please answer with a yes or no.")
...
answered Jan 7, 2012 at 9:25
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1 Comment

sorry im really new and although iv heard of both of these i havent yet learnt them. would you care to explain or give an example
1

And now for a completely different thing:

options = {'intro':"Hi, I'm a PC and my name is Micro, What's your name? > ",
 'ask': "Hi %s how are you, are you good? > ",
 'yes': "That's good to hear!",
 'no': "Oh well",
 'error':"Sorry, you didnt answer the question properly\n",
 'hint': "Please answer with yes/no"}
name = raw_input(options['intro'])
while True:
 try:
 answer = raw_input(options['ask'] % name)
 print options[answer.lower()]
 break
 except KeyError:
 print options['error'], options['hint'] 

As you said you are a noob in Python, I wanted to introduce here several new things to complement the other answer you may find useful.

answered Jan 7, 2012 at 11:20

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