get URI part of instance in SWRL rules

Question

I have some instances created by makeOWLThing , they have some random string, like abc123. They appear in protege as abc123 and in their details, their URI is example.com#abc123

How can I extract the abc123 part of the URI, in SWRL? I want to use it as a string in swrlb:stringConcat . Something like

ns0:modification(?o, ?m) ^ 
swrlx:makeOWLThing(?s, ?m) ^ # new ?s has URI example.com#abc123
rdfs:uriName(?, ?name) ^ # get the abc123 part
swrlb:stringConcat(?newname, "hello_", ?name) # concat hello_abc123
-> 
ss:general(?s) ^ 
ss:generalLabel(?s, ?newname) # pass hello_abc123 as label

So, ?name is a string abc123 and ?newname should be hello_abc123 , that is going to be the label of general's label.

rdfs:uriName(?, ?name) is not a real property, its an example to help you understand what I want and what is my logic

How can I do that ?

• UninformedUser: if you know the namespace in advance, you can use one of string built-ins of SWRL, or not? like swrlb:substringAfter or swrlb:replace does not work?
• slevin: @UninformedUser good idea, i will try it and let you know
• slevin: @UninformedUser check my comments under the answer of user16930239. Thanks

Answer 1

Try this:

ns0:modification(?o, ?m) ^ 
swrlx:makeOWLThing(?s, ?m) ^ 
swrlb:substringAfter(?s, "http://example.com#", ?name) ^ 
swrlb:stringConcat("hello_", ?name, ?newname) ^ 
-> 
ss:general(?s) ^ 
ss:generalLabel(?s, ?newname)

• slevin: nice try, but , first of all, the right syntax for swrlb:substringAfter must be (?newString, ?string, "character") . In my case, swrlb:substringAfter(?newName, ?s, "#") . But another issue is that ?s is not a string, so I get an error. I could first use something like getURI() to get it as a string, but it is native to Apache jenna , not protege. Any other ideas ? Thanks