Make multiple calls asterisk ari python

Question

I wrote a script on python 3 that makes only one call, if the caller answered, then we play the melody and hang up. I use ari asterisk. How can this be done for only a few numbers?

#!/usr/bin/env python3
import json
import sys
import websocket
import requests
import time
class ARIInterface(object):
 def __init__(self, server_addr, username, password):
 self._req_base = "http://%s:8088/ari/" % server_addr
 self._username = username
 self._password = password
 def answer_call(self, channel_id):
 req_str = self._req_base + "channels/%s/answer" % channel_id
 self._send_post_request(req_str)
 def play_sound(self, channel_id, sound_name):
 req_str = self._req_base + ("channels/%s/play?media=sound:%s" % (channel_id, sound_name))
 self._send_post_request(req_str)
 def cr_channel(self, number):
 req_str = self._req_base + ("channels/create?endpoint=SIP/25002/%s&app=hello" % (number))
 self._send_post_request(req_str)
 def dial_channel(self, channel_id):
 req_str = self._req_base + ("channels/%s/dial?timeout=30" % (channel_id))
 self._send_post_request(req_str)
 def del_channel(self, channel_id):
 req_str = self._req_base + ("channels/%s" % (channel_id))
 self._send_delete_request(req_str)
 def _send_post_request(self, req_str):
 r = requests.post(req_str, auth=(self._username, self._password))
 def _send_delete_request(self, req_str):
 r = requests.delete(req_str, auth=(self._username, self._password))
class ARIApp(object):
 def __init__(self, server_addr):
 app_name = 'hello'
 username = 'ari-user'
 password = 'ari-ewsd-135'
 url = "ws://%s:8088/ari/events?app=%s&api_key=%s:%s" % (server_addr, app_name, username, password)
 ari = ARIInterface(server_addr, username, password)
 ws = websocket.create_connection(url)
 numbers = [21018, 35000]
 ari.cr_channel('21018')
 channel_id = json.loads(ws.recv())['channel']['id']
 ari.dial_channel(channel_id)
 try:
 for event_str in iter(lambda: ws.recv(), None):
 event_json = json.loads(event_str)
 json.dump(event_json, sys.stdout, indent=2, sort_keys=True,
 separators=(',', ': '))
 print("\n\nWebsocket event***************************************************\n")
 try:
 if event_json['dialstatus'] == 'ANSWER':
 peer_id = event_json['peer']['id']
 ari.play_sound(peer_id, 'hello-world')
 time.sleep(2)
 ari.del_channel(peer_id)
 except:
 pass
 except websocket.WebSocketConnectionClosedException:
 print("Websocket connection closed")
 except KeyboardInterrupt:
 print("Keyboard interrupt")
 finally:
 if ws:
 ws.close()
if __name__ == "__main__":
 app = ARIApp('localhost')

I tried to change the Ariapp class as follows:

class ARIApp(object):
 def __init__(self, server_addr):
 app_name = 'hello'
 username = 'ari-user'
 password = 'ari-ewsd-135'
 url = "ws://%s:8088/ari/events?app=%s&api_key=%s:%s" % (server_addr, app_name, username, password)
 ari = ARIInterface(server_addr, username, password)
 ws = websocket.create_connection(url)
 numbers = [21018, 35000]
 
 for number in numbers: 
 ari.cr_channel(number)
 channel_id = json.loads(ws.recv())['channel']['id']
 ari.dial_channel(channel_id)
 try:
 for event_str in iter(lambda: ws.recv(), None):
 event_json = json.loads(event_str)
 json.dump(event_json, sys.stdout, indent=2, sort_keys=True,
 separators=(',', ': '))
 print("\n\nWebsocket event***************************************************\n")
 try:
 if event_json['dialstatus'] == 'ANSWER':
 peer_id = event_json['peer']['id']
 ari.play_sound(peer_id, 'hello-world')
 time.sleep(2)
 ari.del_channel(peer_id)
 except:
 pass
 except websocket.WebSocketConnectionClosedException:
 print("Websocket connection closed")
 except KeyboardInterrupt:
 print("Keyboard interrupt")
 finally:
 if ws:
 ws.close()

• royun: I wanted to fix the code, but the forum won't let me do it.
• arheops: you need more reputation and thats all.

Answer 1

You can add as many channels as you want. There is no limit

You should use Originate AMI call or call files if you want independent channels

• royun: Is it really impossible to implement this on an ami?
• arheops: What? AMI has action Originate.
• royun: Indeed, I can make one call without any problems. It is not possible to make exactly several calls.
• arheops: Do it twice? What prevent you from doing that?
• royun: I apologize for not responding for a long time. I made a typo at the top, I meant ARI. Is it possible to make multiple calls using the API?