246

Say I've got this

imageList = [100,200,300,400,500];

Which gives me

[0]100 [1]200 etc.

Is there any way in JavaScript to return the index with the value?

I.e. I want the index for 200, I get returned 1.

TylerH
21.2k83 gold badges83 silver badges120 bronze badges
asked Sep 8, 2011 at 10:47
2

12 Answers 12

374

You can use indexOf:

var imageList = [100,200,300,400,500];
var index = imageList.indexOf(200); // 1

You will get -1 if it cannot find a value in the array.

answered Sep 8, 2011 at 10:49

5 Comments

you can use developer.mozilla.org/en/JavaScript/Reference/Global_Objects/… or any Javascript framework to fix that.
Have just found it won't work in IE8. What's my alternative?
@voigtan How do I add this to my JS?
I've done it, thanks. IE will one day catch up with modern times!
Also won't work in recent IE if in compatibility mode
106

For objects array use map with indexOf:

var imageList = [
 {value: 100},
 {value: 200},
 {value: 300},
 {value: 400},
 {value: 500}
];
var index = imageList.map(function (img) { return img.value; }).indexOf(200);
console.log(index);


In modern browsers you can use findIndex:

var imageList = [
 {value: 100},
 {value: 200},
 {value: 300},
 {value: 400},
 {value: 500}
];
var index = imageList.findIndex(img => img.value === 200);
console.log(index);

Its part of ES6 and supported by Chrome, FF, Safari and Edge

answered May 17, 2016 at 10:57

2 Comments

Note that findIndex is not implemented in IE 11
@Bindrid it is written in the answer see "Its part of ES6 and supported by Chrome, FF, Safari and (Unfortunately only) IE edge"
18

Use jQuery's function jQuery.inArray

jQuery.inArray( value, array [, fromIndex ] )
(or) $.inArray( value, array [, fromIndex ] )
answered Mar 10, 2013 at 4:20

2 Comments

Was going to use the code marked as the correct answer but it seems that that code wont work in all versions of IE. This answer works in all versions of IE but I changed the code slightly: var arrayPosition = $.inArray( value, Array ); works perfectly
jQuery ≠ Javascript
17

Here is an another way find value index in complex array in javascript. Hope help somebody indeed. Let us assume we have a JavaScript array as following,

var studentsArray =
 [
 {
 "rollnumber": 1,
 "name": "dj",
 "subject": "physics"
 },
 {
 "rollnumber": 2,
 "name": "tanmay",
 "subject": "biology"
 },
 {
 "rollnumber": 3,
 "name": "amit",
 "subject": "chemistry"
 },
 ];

Now if we have a requirement to select a particular object in the array. Let us assume that we want to find index of student with name Tanmay.

We can do that by iterating through the array and comparing value at the given key.

function functiontofindIndexByKeyValue(arraytosearch, key, valuetosearch) {
 for (var i = 0; i < arraytosearch.length; i++) {
 if (arraytosearch[i][key] == valuetosearch) {
 return i;
 }
 }
 return null;
 }

You can use the function to find index of a particular element as below,

var index = functiontofindIndexByKeyValue(studentsArray, "name", "tanmay");
alert(index);
answered Aug 12, 2015 at 12:51

Comments

10

Use indexOf

imageList.indexOf(200)
answered Sep 8, 2011 at 10:50

Comments

8

how about indexOf ?

alert(imageList.indexOf(200));
answered Sep 8, 2011 at 10:51

Comments

7

Array.indexOf doesnt work in some versions of internet explorer - there are lots of alternative ways of doing it though ... see this question / answer : How do I check if an array includes an object in JavaScript?

answered Sep 8, 2011 at 10:55

2 Comments

according to this page developer.mozilla.org/en-US/docs/JavaScript/Reference/… you need Internet Explorer 9 for this feature (I almost wrongly assumed we were just talking IE 6 here)
@Simon_Weaver on that page you linked there is a polyfill for all browsers using JavaScript 1.6 and up
6

When the lists aren't extremely long, this is the best way I know:

function getIndex(val) {
 for (var i = 0; i < imageList.length; i++) {
 if (imageList[i] === val) {
 return i;
 }
 }
}
var imageList = [100, 200, 300, 400, 500];
var index = getIndex(200);
answered Mar 21, 2015 at 7:59

Comments

6

It is possible to use a ES6 function Array.prototype.findIndex.

MDN says:

The findIndex() method returns the index of the first element in the array that satisfies the provided testing function. Otherwise -1 is returned.

var fooArray = [5, 10, 15, 20, 25];
console.log(fooArray.findIndex(num=> { return num > 5; }));
// expected output: 1

Find an index by object property.

To find an index by object property:

yourArray.findIndex(obj => obj['propertyName'] === yourValue)

For example, there is a such array:

let someArray = [
 { property: 'OutDate' },
 { property: 'BeginDate'},
 { property: 'CarNumber' },
 { property: 'FirstName'}
];

Then, code to find an index of necessary property looks like that:

let carIndex = someArray.findIndex( filterCarObj=> 
 filterCarObj['property'] === 'CarNumber');
answered Dec 27, 2017 at 7:02

Comments

4

In a multidimensional array.


Reference array:

var array = [
 { ID: '100' },
 { ID: '200' },
 { ID: '300' },
 { ID: '400' },
 { ID: '500' }
];

Using filter and indexOf:

var index = array.indexOf(array.filter(function(item) { return item.ID == '200' })[0]);

Looping through each item in the array using indexOf:

for (var i = 0; i < array.length; i++) {
 var item = array[i];
 if (item.ID == '200') { 
 var index = array.indexOf(item);
 }
}
answered Feb 17, 2020 at 19:29

Comments

0

Here is my take on it, seems like most peoples solutions don't check if the item exists and it removes random values if it does not exist.

First check if the element exists by looking for it's index. If it does exist, remove it by its index using the splice method

elementPosition = array.indexOf(value);
if(elementPosition != -1) {
 array.splice(elementPosition, 1);
}
answered Sep 24, 2018 at 17:35

Comments

-1
// Instead Of 
var index = arr.indexOf(200)
// Use 
var index = arr.includes(200);

Please Note: Includes function is a simple instance method on the array and helps to easily find if an item is in the array(including NaN unlike indexOf)

answered Apr 10, 2018 at 10:18

2 Comments

In addition to this only telling you if it exists, instead of getting the index/item, be cognizant of the compatibility (i.e. no IE): caniuse.com/#search=includes

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.