I'm trying to remove the empty strings in my array.
This is my array:
let array = [
{ name: 'John', age: '18', address: '' },
{ name: 'George', age: '', address: '' },
{ name: 'Kevin', age: '25', address: '' }
]
I would like to remove the empty string values ONLY if it's empty in all objects.
desired outcome:
[
{ name:'John', age:'18' },
{ name:'George', age:'' },
{ name:'Kevin', age:'25' }
]
This is what I did but it removes EVERY empty string values:
for (let i = 0; i < array.length; i++) {
array[i] = Object.fromEntries(Object.entries(array[i]).filter(([_, v]) => v != ''));
}
VLAZ
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Can we assume that all objects in the array are the same (i.e. contain the same set of properties)?yuvin– yuvin2022年04月13日 08:10:03 +00:00Commented Apr 13, 2022 at 8:10
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@yuvin Yes , all objects are the sameBar Levin– Bar Levin2022年04月13日 08:10:53 +00:00Commented Apr 13, 2022 at 8:10
3 Answers 3
If you don't mind mutating the original array object. Here's a solution utilizing some array functions.
let array = [
{ name: 'John', age: '18', address: '' },
{ name: 'George', age: '', address: '' },
{ name: 'Kevin', age: '25', address: '' }
]
Object.keys(array[0])
.filter(k => array.every(obj => !obj[k]))
.forEach(k => array.forEach(obj => delete obj[k]));
console.log(array);
answered Apr 13, 2022 at 8:20
Hao Wu
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You can solve this issue with a filter method
- get all the entries to be scanned in the array;
- for each entry, filter the array with it; if the output array is empty then you can delete this value in the original array
let array = [{name:'John',age:'18',address:''},{name:'George',age:'',address:''},{name:'Kevin',age:'25',address:''}]
const entries = Object.keys(array[0])
entries.forEach(e => {
if (array.filter(i => i[e]).length === 0) {
array = array.map(i => {
delete i[e];
return i
})
}
})
console.log(array)
Comments
If you don't want to mutate the original array:
let array = [{name:'John',age:'18',address:''},{name:'George',age:'',address:''},{name:'Kevin',age:'25',address:''}]
let result;
Object.keys(array[0])
.forEach(key => {
if(array.every(e => e[key] === ''))
result = array.map(({[key]:_,...rest}) => ({...rest}))
})
console.log(result)
answered Apr 13, 2022 at 8:48
Alan Omar
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