Python check operation calculator

Question

I want to check operator and result print only as number, not in brackets. But I do not know how to add it in my code. Ideally check numbers as float.

 texts = ["give first number: ",
 "give operator: ", "give second number: "]
allowed_operators = ['+', '-', '/', '*', '**', '%']
def calculate(value_list):
 #[ 1, "+", 1]
 num1, operator, num2 = value_list
 if operator == '+':
 return num1 + num2
 elif operator == '-':
 return num1 - num2
 elif operator == '*':
 return num1 * num2
 elif operator == '**':
 return num1 ** num2
 elif operator == '/':
 return num1 / num2
 elif operator == '%':
 return num1 % num2
 
last_result = None
while True:
 values = [] 
 i = 0
 
 while i < 3:
 value = input("give value: ")
 if value == "q":
 exit(0)
 if value in allowed_operators:
 values.append(value) # [+]
 else:
 values.append(float(value))
 
 if value in allowed_operators and i == 0:
 if last_result == None: 
 print("Last calculation does not exist. ")
 continue
 else:
 values.insert(0, last_result)
 i += 1 
 i += 1
 print(values)
 result = calculate(values)
 print(f'Result: {result}')
 last_result = result

• juagicre: Does this answer your question? Basic Python calculator

Answer 1

Not sure if I understand your problem correctly, but if you want to print the intermediate calculation without brackets then change

print(values)

to

print(" ".join(str(value) for value in values))

Answer 2

Not sure what you need, but the calculation function can use operator module:

import operator
def calculate(value_list):
 # [ 1, "+", 1]
 num1, flag, num2 = value_list
 flag_func = {'+': 'add', '-': 'sub', '*': 'mul', '**': 'pow', '/': 'truediv', '%': 'mod'}
 if func := flag_func.get(flag):
 return getattr(operator, func)(num1, num2)
 raise Exception(f'Invalid operate {flag=}')