How to execute a function inside a python script?

Question

How can I execute the below simple script called foo.py from the (bash) command line?

def hello():
 return 'Hi :)'

I tried the following and got an error.

 $ python -c 'import foo; print foo.hello()'
 File "<string>", line 1
 import foo; print foo.hello()
 ^
SyntaxError: invalid syntax

I'm able to execute the following but just receive no output.

$ python foo.py
$

• sc0rp10n.my7h: Use python foo.py this is correct. You didn't receive an output because you didn't call the function, you just defined it. def hello(): return 'Hi :)' print hello()
• Ahsan Goheer: Try python -c "import foo; print(foo.hello())"
• jgg: @AhsanGoheer I get a greater than sign. $ python -c "import foo; print(foo.hello()) >
• Ahsan Goheer: @jgg you get the greater than sign as an output?
• jgg: @AhsanGoheer Yes I got the greater than sign. I think it was because of the double quotes. Once I changed to single quotes it worked.

Answer 1

print foo.hello()

Is this Python2?

remove that print before function call:

$ python -c 'import foo; foo.hello()'

Or make it like python3 syntax:

$ python -c 'import foo; print(foo.hello())'

Answer 2

If you're using python 2.x, use:

import foo; print foo.hello()

However, on python 3.x brackets are required:

import foo; print(foo.hello())

Answer 3

maybe your Python version is 3.x

On Python3 print should have "()"

you can try

print(foo.hello())