JavaScript - Need help with string manipulation

Question

say you have:

var foo = "donut [25ドル]"

What would you need to do in order to delete everything between and including the [ ].

so you get: foo = "donut" after the code is run.

So far I have tried most of the solutions below, but they all either do nothing or crash. Maybe it's something with my code, please see below:

 $('select').change(function () { OnSuccess(mydata); });
 function OnSuccess(data) {
 var total = 0;
 $('select').each(function () {
 var sov = parseInt($(this).find('option:selected').attr('value')) || 0; //Selected option value
 var sop; //Selected Option Price
 for (i = 0; i <= data.length; i++) {
 if (data[i].partid == sov) {
 sop = data[i].price;
 total += sop;
 $('#totalprice').html(total);
 break;
 }
 };
 //debugger;
 $(this).find('option').each(function () {
 // $(this).append('<span></span>');
 var uov = parseInt($(this).attr('value')) || 0; //Unselected option value
 var uop; //Unselected Option Price
 for (d = 0; d <= data.length; d++) {
 if (data[d].partid == uov) {
 uop = data[d].price;
 break;
 }
 }
 //debugger;
 var newtext = uop - sop;
 //{ newtext = "" };
 //if (newtext = 0) { newtext.toString; newtext = ""; };
 //debugger;
 var xtext = $(this).text().toString();
 //if (xtext.match(/\[.*\]/) != null) {
 xtext.replace(/\s*\[[\s\S]*?\]\s*/g, '').trim();
 //}
 // var temp = xtext.split('[')[0];
 // var temp2 = xtext.split(']')[1];
 // resultx = temp + temp2;
 if (newtext != 0) {
 //xtext.replace(/[.*?]/, "");
 $(this).attr("text", xtext + " " + "[" + "$" + newtext + "]");
 };
 });
 });
 };

Answer 1

You can also use a regular expression, as Jon Martin pointed out:

var yum = "donut[25ドル]"; yum.replace(/[.*?]/, ""); // returns "donut"

Answer 2

Alternatively:

var temp = foo.split('[')[0];
var temp2 = foo.split(']')[1];
foo = temp + temp2;

Answer 3

You can use regular expressions (the RegExp() object) to match strings.

var foo = "donut[25ドル]";
foo.match(/\[.*\]/);

The above will return an array of every item in [square brackets], in this case ["[25ドル]"].

To just get one result as a string, specify the first index like so:

foo.match(/\[.*\]/)[0];

The above will return "[25ドル]"

Edit: You know what? I completely misread which bit of the string you're after. This is what you're after:

var foo = "donut[25ドル]";
foo.match(/\w*/)[0];

Answer 4

How about simply;

var yum = "donut[25ドル]";
print( yum.substr(0, yum.indexOf("[")) );
>>donut

• Jon Martin: This won't work for strings that have characters after the ']'.
• Alex K.: It will work for donut[34ドル]weqweqwe as it truncates at the 1st [ which seems reasonable for what appears to be structured data
• Jon Martin: He only wanted to delete everything between [..] inclusively. Your method will delete everything after the ].
• LaserBeak: var xtext = $(this).text().toString(); xtext.substr(0, xtext.indexOf("[")); - Does not seem to be doing anything ?

Answer 5

var begin = foo.search("["); var end = foo.search("]"); var result = foo.substr(0, begin) + foo.substr(end+1); //Combine anything before [ and after ]

Should be ok right?

Answer 6

Your question leaves unspecified the treatment of the spaces before the [ character, anything after the ], will your string ever contain a linefeed character, multiple occurrences of [..], leading or trailing spaces.

The following will replace all occurrences of 'spaces [ ... ] spaces' with a single space, then it trims the result to remove any leading/trailing spaces.

 v.replace (/\s*\[[\s\S]*?\]\s*/g, ' ').trim ();