Remove an array from an Array if a certain value exists in the array in javascript

Question

Trying to remove an entire array if within my data if it contains a certain value.

What would be the best approach to this problem?

data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']]
var del_value = 'J-001';
function remove_from_list(list) {
 for( var i = 0; i < list.length; i++) { 
 for( var j =0; j < Object.keys(list[i]).length.length; j++) {
 if(del_value == list[i][j]) {
 list.splice(list[i], 1);
 }
 }
 }
 return list;
}

actual output

data = 
[['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']]

desired result -- to remove all arrays that have the value 'J-001'

data = 
[['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001']]

• bombombs: @HassanImam yeah, it would be

Answer 1

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']];
const input = "J-001";
// Approach 
// Filter element (use filter) who has not given input (use not includes for this)
const result = data.filter(dat => !dat.includes(input));
console.log(result);

filter includes

Answer 2

You can use array#filter and array#includes to filter based on array not including J-001.

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'], ['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'], ['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'], ['false', 'visiting-tommorrow', 'DVM-Kon','J-001']],
 result = data.filter(arr => !arr.includes('J-001'));
console.log(result);

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If the position of the element is fixed to be third. Then you can use directly compare the value at that index.

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'], ['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'], ['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'], ['false', 'visiting-tommorrow', 'DVM-Kon','J-001']],
 result = data.filter(arr => arr[3] !== 'J-001');
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

Alternate approach using Array.filter() and Array.find().

data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']];
function removeFromList(list, delValue) {
 return list.filter(arr => !arr.find(value => value === delValue));
}
console.log(removeFromList(data, 'J-001'));