Is there a JavaScript Object that is not a function?
javascript: x=y=z=Object; alert([window.navigator.userAgent,x,y,z].join("\n\n"))
(There was a comment that x,y,z are merely references in which case Object is also merely a reference to function Object(){ ... } because Object's value is assigned to x and they are the "same". As "proof"
javascript:x=Object;x.p=43;alert([x==Object,x===Object,x.p,Object.p])
displays
true,true,43,43
Given function Thing(){} does x=new Thing() make x an object or a reference to one? What about new Thing() and Thing? Or y in y=x=new Thing() or y=x=Thing? What if Thing=function(){}? The distinction is moot. "Everything" (or is it?) is called-by-reference but call-by-name can be coerced by evaluating strings. So ...)
javascript:
void function(x,y,z){
alert( [window.navigator.userAgent,x,y,z].join("\n\n") )
}(Object,Object,Object)
or
javascript:
void function(x){ (function (y){ (function (z){
alert( [window.navigator.userAgent,x,y,z].join("\n\n") )
})(y) })(x) }(Object)
(well not quite moot - the function's values must be coerced using (...) or void. The nuances of (...) are subtle:
javascript: /* 43.p gives a runtime error but not ... */
alert([ (43).p=34, 43["q"]=17, (x=43).z="hmmm" ]);
alert([ 43["p"], (43).z, x.p, x["z"], x]);
displays 34,17,hmmm and ,,,,43
)
or even an array of Objects
javascript:alert([window.navigator.userAgent,Object,Object,Object].join("\n\n"))
gives:
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.2.3) Gecko/20100423 Ubuntu/10.04 (lucid) Firefox/3.6.3
function Object() { [native code] }
function Object() { [native code] }
function Object() { [native code] }
There are many objects that are not Object.
As pointed out in one of the answers, Object may not be itself IF it is modified.
Danger! Danger! Will Robinson!
x=y=z=Object=null; alert([window.navigator.userAgent,Object,x,y,z].join("\n\n"));
references
- Object and Function are quite confusing
- Difference between a constructor and an Object
- Is Function really an Object
- Is JavaScript function a "function" or an "object" or both?
- Every Object is a function and every function is Object - Which is Correct?
- Why in JavaScript is a function considered both a constructor and an object?
4 Answers 4
You didn't create objects, you created references to the Object function. If you wanted those to be objects you could do this:
x = y = z = {}
Then alert(x) will return object [Object].
To (hopefully) encompass the comments - by default Object is a Function which constructs Objects. If you reassign the name Object (Firefox at least seems to allow me to, haven't tested all browsers) then Object will no longer be a Function, it will be whatever you assigned to it. So then, the answer is "no", Object is not always a Function, but should be unless it has been explicitly re-declared. According to Firebug:
>>> Object
Object()
>>> Object = {}
Object {}
>>> Object
Object {}
Seemingly it can be reassigned. I cannot vouch for what kind of impacts that would have, if any.
6 Comments
Object = {} to turn it into an actual Object Literal, but this eliminates the ability to call new Object() as you've overwritten the previous signature. I ... am not certain I grasp why you are asking in the way you are asking.x, y and z ARE objects - (albeit the same one) - they are the (one and only) Object object which is an object of type function or simply a function.You are assigning the Object constructor to the vars x, y and z.
If you instead say x=new Object(), you will no longer see them referred to as functions.
4 Comments
Any function can be used as a constructor to create an object by using the new operator before the function name in JavaScript. The resulting object will not be a Function.
There is also a circular relationship between Object and Function that can be tested with:
Object instanceof Function // true
Function instanceof Object // true
And {} and Object are not the same, but {} and new Object() are.
function foo() {}
foo instanceof Function // true
foo instanceof Object // true
var bar = new foo();
bar instanceof Function // false
bar instanceof Object // true
var baz = {};
baz instanceof Function; // false
baz instanceof Object; // true
4 Comments
new operator ... will not be a Function" is not true, proof: javascript:function f(){return function(){}};alert(new f)javascript:with(Object)alert([Object,constructor,prototype.constructor ]) details are provided in chat.stackoverflow.com/rooms/2245/… Here is a surefire way to check the type of anything in js.
note: you should send in something other than window...
(function (self) {
var values = [
'Function',
'Object',
'Array',
'String',
'Number',
'Date',
'RegExp',
'Boolean',
'Null',
'Error'
];
for (var i in values) if (values.hasOwnProperty(i)) {
var value = values[i];
self['is' + value] = (function (v) {
return function (o) {
var r = '';
try {
r = (o === null) ?
'Null' :
Object.prototype.toString.call(o).replace(/^\[object\s(\w+)\]$/, '1ドル');
} catch (e) {
r = 'Undefined';
}
return !!(r === v);
};
})(value);
}
})(window);
alert(isFunction(Object));
Objectisfunction Object() { [native code] }viajavascript:alert(Object)and so ...