How to get particular data values from JSON Node.js?

Question

This is my JSON file output:

let employees = [{
 "id":1,
 "name":"Lann",
 "username":"brot",
 "email":"[email protected]",
 "address": {
 "city":"Gweh",
 "zipcode":"92998-3874",
 "geo": {
 "lat":"45",
 "lng":"77"
 }
 }
}]

How I get id, name and email from that like below:

{
 "id":1,
 "name":"Lann",
 "email":"[email protected]"
}

• Philippe: Hi ! Your json input is malformed : missing }, ie }] should be }}] Whith a correct input, you can console.log(employees[0].name); for example.

Answer 1

If your array has only one element you can just access the info, no need to build another array like this: employees[0].id , employees[0].name, employees[0].email or you can just extract an object using Object Destructuring

let employees = [{
 "id": 1,
 "name": "Lann",
 "username": "brot",
 "email": "[email protected]",
 "address": {
 "city": "Gweh",
 "zipcode": "92998-3874",
 "geo": {
 "lat": "45",
 "lng": "77"
 }
 }
}];
const picked = (({ id, name, email }) => ({ id, name, email }))(employees[0]);
console.log(picked);

but if your array has more employees, i think what you need to do is search by id or name and get back just an object with minimal info, you can do that like this

let employees = [{
 "id": 1,
 "name": "Lann",
 "username": "brot",
 "email": "[email protected]",
 "address": {
 "city": "Gweh",
 "zipcode": "92998-3874",
 "geo": {
 "lat": "45",
 "lng": "77"
 }
 }
}];
let employee = employees.find(o => o.name === 'Lann');
let picked = (({ id, name,email }) => ({ id, name,email }))(employee);
console.log(picked);

Answer 2

You can archive using map.

let employees = [{
 "id":1,
 "name":"Lann",
 "username":"brot",
 "email":"[email protected]",
 "address":{
 "city":"Gweh",
 "zipcode":"92998-3874",
 "geo":{
 "lat":"45",
 "lng":"77"
 }
 }
 }]
const data = employees.map(o => ({ id: o.id, name: o.name, email:o.email }));
console.log(data[0]);

Answer 3

You can simply do this by using array destructuring.

let employees = [{
 "id":1,
 "name":"Lann",
 "username":"brot",
 "email":"[email protected]",
 "address":{
 "city":"Gweh",
 "zipcode":"92998-3874",
 "geo":{
 "lat":"45",
 "lng":"77"
 }
 }}];
// Destructuring array
const [employee] = employees;

** Now from here employee is an object and you can access its property normally as you do with other objects. For getting id, name, username:**

employee.id;
employee.name;
employee.username;

Answer 4

You cans also loop through your input if it contains multiple items and get an array of shrink items :

let employees = [{
 "id": 1,
 "name": "Lann",
 "username": "brot",
 "email": "[email protected]",
 "address": {
 "city": "Gweh",
 "zipcode": "92998-3874",
 "geo": {
 "lat": "45",
 "lng": "77"
 }
 }
}]
let shrink = [];
for (let employee of employees) {
 shrink.push({
 id: employee.id,
 name: employee.name,
 email: employee.email
 });
}
console.log(shrink);