Repeated while loop with boolean

Question

Sorry if this is considered spam, yet another issue I have is that this while loop runs unconditionally and I am not sure how to fix it.

Code:

while anotherNum == True:
 playerNum = random.randint(1,10)
 total = total + playerNum
 print("")
 print("Your number is ", str(playerNum) + ".")
 print("You have " + str(total) + " in total.")
 print("")
 again = input("Roll another number? <Y or N> ")
 print("")
 if again == "Y":
 anotherNum == True
 else:
 anotherNum == False
 break
 #game finished now
print("Computer got", pcNum)
print("You got", total)
#checking for winner
while anotherNum == False:
 if (total <= 13) and (total > pcNum): 
 print("You,", name, "have won!")
 elif (pcNum <= 13) and (pcNum > total):
 print("The computer has bested you,", name + "!")
 else:
 if (total == pcNum) and (total <= 13):
 print("Draw...")
 elif (pcNum > 13) and (total <= 13):
 print("You,", name + " have won!")
 else:
 print("Both of you have lost. Wow...")

Output:

Your number is 2.
You have 2 in total.
Roll another number? <Y or N> n
Your number is 3.
You have 3 in total.
Roll another number? <Y or N> N
Your number is 3.
You have 3 in total.
Roll another number? <Y or N> N
Your number is 9.
You have 9 in total.

Instead of going to the #game finished now comment's area, the while loop repeats the process whilst only disregarding the total = total + playerNum command.

Answer 1

You are not changing the valu

if again == "Y":
 anotherNum == True
 else:
 anotherNum == False
 break

You should use 1 equal sign as it is an assignment

if again == "Y":
 anotherNum = True
 else:
 anotherNum = False
 break

Answer 2

Your code (with minimal correction) is working just fine:

import random
total = 0
anotherNum = True
while anotherNum == True:
 playerNum = random.randint(1,10)
 total = total + playerNum
 print("")
 print("Your number is ", str(playerNum) + ".")
 print("You have " + str(total) + " in total.")
 print("")
 again = input("Roll another number? <y or n> ")
 print("")
 if again == "y":
 anotherNum = True
 else:
 anotherNum = False
 break
print("You got", total)

The output that I get after running the code:

Your number is 7.
You have 7 in total.
Roll another number? <y or n> y
Your number is 9.
You have 16 in total.
Roll another number? <y or n> y
Your number is 10.
You have 26 in total.
Roll another number? <y or n> y
Your number is 2.
You have 28 in total.
Roll another number? <y or n> y
Your number is 6.
You have 34 in total.
Roll another number? <y or n> n
You got 34

Answer 3

Here's how I would do it.

while anotherNum:
 playerNum = random.randint(1,10)
 total += playerNum
 print("")
 print("Your number is ", str(playerNum) + ".")
 print("You have " + str(total) + " in total.")
 print("")
 again = input("Roll another number? <Y or N> ")
 print("")
 anotherNum = (again == "Y")

this way you can avoid the if <blank> then true else false which caused you to make a mistake here (simple == instead of =)

• fleur333: I still have the same issue.
• Alex SHP: Are you sure that you're inputing "Y" , not "y" ? That will cause issues... Try to print again to make sure ? And please note that the first = is only one character and the second is "=="

Answer 4

Try to remove break and change == to =

import random
total = 0
anotherNum = True
while anotherNum == True:
 playerNum = random.randint(1, 10)
 total += playerNum
 print("")
 print(f"Your number is {playerNum}.")
 print(f"You have {total} in total.")
 print("")
 again = input("Roll another number? <Y or N> ")
 print("")
 if again == "Y":
 anotherNum = True # <- HERE
 else:
 anotherNum = False # <- HERE

OR without anotherNum variable:

import random
total = 0
while True:
 playerNum = random.randint(1, 10)
 total += playerNum
 print("")
 print(f"Your number is {playerNum}.")
 print(f"You have {total} in total.")
 print("")
 again = input("Roll another number? <Y or N> ")
 print("")
 if again == 'N':
 break