2

I am writing a function that will iterate through an of objects to find if key:value pair exists and if so, it adds into another array (in case there are multiple matches)

The array contains objects. The function takes as argument what key and value you're looking for and then iterates through array till it finds it. As you can see, key is a variable then and my problem is I am not sure how to access object property when referring to as a variable value.

for (let i = 0; i < arr.length; i++) {
 if (arr[i].[key] == value) {
 result.push(arr[i]);
 }
}

I thought maybe putting it in [key] would help, but I was obviously wrong. I tried googling how to do it, but I guess i can't put it in words right .

mplungjan
180k29 gold badges183 silver badges246 bronze badges
asked Sep 8, 2021 at 15:56

4 Answers 4

2

You are confusing dot notation with bracket notation.

Remove the .; arr[i].[key] == value1 should be arr[i][key] == value.

const arr = [{
 'a': 'b'
}]
key = 'a'
value = 'b'
const result = []
for (let i = 0; i < arr.length; i++) {
 if (arr[i][key] == value) {
 result.push(arr[i]);
 }
}
console.log(result)

You can simplify the code by using filter:

const arr = [{
 'a': 'b'
}]
key = 'a'
value = 'b'
const result = arr.filter(e => e[key] == value)
console.log(result)

answered Sep 8, 2021 at 15:59
Sign up to request clarification or add additional context in comments.

Comments

1

You can use ES6+ and ternary true ( && == only true action )

const arr = [{
 a: 'b'
}];
const key = 'a';
const value = 'b';
const result = [];
for (const item of arr) {
 (item[key] === value) && result.push(item)
};
console.log(result);

You can simplify the code by using filter:

const arr = [{
 a: 'b'
}];
const key = 'a';
const value = 'b';
const result = [];
for( const item of arr ) {
 ( item[key] === value ) && result.push( item )
};
console.log( result );

Comments

0

const arr = [
 {name:"Evan", age:28},
 {name:"John", age:23},
 {name:"Anne", age:28},
];
const searchProp = "age";
const searchValue = 28;
const result = arr.filter((user) => user[searchProp] === searchValue);
console.log(result)

answered Sep 8, 2021 at 16:02

Comments

0

You are almost there, just get rid of the extra . between [i] and [key]:

for (let i = 0; i < arr.length; i++) {
 if (arr[i][key] == value) {
 result.push(arr[i]);
 }
}

However, there would be a simpler and more straight-forward way, using filter:

const result = arr.filter(obj => obj[key] == value)

Example:

const arr = [
 { a: 1, b: 1 },
 { a: 1, b: 2 },
 { a: 2, b: 1 },
 { a: 2, b: 2 }
]
const key = 'b'
const value = 1
const result = arr.filter(obj => obj[key] == value)
console.log(result)
// Output: [{ a: 1, b: 1 }, { a: 2, b: 1 }]

answered Sep 8, 2021 at 15:59

Comments

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.