2

I have loaded a data from API and displayed here with VueJS. I have users information inside users[] array. I also have users with two types of plan: basic_plan and standard_plan. Currently it shows all users.

Now I want to apply filters equally to this example: https://codepen.io/marn/pen/jeyXKL?editors=0010

I also got an error filter not defined

Filters:

 <input type="radio" v-model="selectedItems" value="All" /> All
 <input type="radio" v-model="selectedItems" value="basic_plan" /> Basic
<ul
 v-for="(user, index) in selectedUser.data"
 :key="index"
 class="watchers divide-y divide-gray-200"
 >
 <li class="py-4">
 <div class="mx-4 flex space-x-3">
 <span
 class="inline-flex items-center justify-center h-8 w-8 rounded-full bg-gray-500"
 >
 
 </span>
 <div class="flex-1 space-y-1">
 <h3 class="text-sm font-medium">
 {{ user.name }}
 </h3>
 <div class="flex items-center justify-between">
 <p class="text-sm font-medium text-indigo-500">
 {{ user.plan }}
 </p>
 
 
 </div>
 </div>
 </div>
 </li>
 </ul>
 
 </div>
</template>
<script 
export default {
 data() {
 return {
 users: [],
 selectedItems:"All"
 };
 },
 created() {
 this. users();
 },
 methods: {
 users {
 axios
 .get('api/users')
 .then(response => {
 
 this.users = response.data;
 
 }
 },
computed: {
 selectedUser: function() {
 
 if(this.selectedItems ==="All"){
 return this.users
 }else{
 return this.users.data.filter(function(item) {
 console.log(item)
 return item.plan === this.selectedItems;
 });
 }
 }
 }
};
</script>

when All is selected vue dev tool shows this

selectedUser:Object //OBJECT SHOWING
data:Array[10]
links:Object
meta:Object
but when basic radio is selected vue shows this
selectedUser:Array[1] //ARRAY SHOWING
0:Object
price:"10"
plan:"basic_planl"
Michael W. Czechowski
3,4452 gold badges26 silver badges52 bronze badges
asked Jul 27, 2021 at 12:41
1
  • 1
    Try to change inside computed.selectedUser() return this.users.data.filter into return this.users.filter, because you have already applied the data property from your response onto this.users. Commented Jul 27, 2021 at 12:47

2 Answers 2

1

If you want to filter out specific users you must apply the "filter" function to the users variable like this: this.users.filter(...)

With this function you then can filter the users based on their plan like this:

this.users.filter((user) => 
 user.plan === this.selectedItems;
});

For a modern approach I used an arrow function. And without using curly brackets the statement inside the function is returned by default, so that's why there is no "return" statement.

answered Jul 27, 2021 at 13:37
Sign up to request clarification or add additional context in comments.

Comments

0

Try this way instead, as you are already using v-for in your HTML, you can conveniently filter out users without any more loops, if you are getting value as "basic_plan" in the "user.plan" key.

Also, I think that you should move your v-for to <li> tag instead of <ul> along with the validation on <ul> if there are no users in the array.

<template>
 <div>
 <input type="radio" v-model="selectedItems" value="All" /> All
 <input type="radio" v-model="selectedItems" value="basic_plan" /> Basic
 
 <ul v-if="selectedUser.data.length" class="watchers divide-y divide-gray-200">
 <li v-for="(user, index) in selectedUser.data" :key="index" class="py-4">
 <div v-if="filterUser(user)" class="mx-4 flex space-x-3">
 <span class="inline-flex items-center justify-center h-8 w-8 rounded-full bg-gray-500"></span>
 <div class="flex-1 space-y-1">
 <h3 class="text-sm font-medium">
 {{ user.name }}
 </h3>
 <div class="flex items-center justify-between">
 <p class="text-sm font-medium text-indigo-500">
 {{ user.plan }}
 </p>
 </div>
 </div>
 </div>
 </li>
 </ul>
 </div>
</template>
<script>
export default {
 data() {
 return {
 users: [],
 selectedItems:"All"
 };
 },
 methods: {
 filterUser(user){
 if(this.selectedItems === 'All'){
 return true;
 }
 if(this.selectedItems === 'basic_plan'){
 return this.selectedItems === user.plan;
 }
 }
 },
}
</script>
answered Jul 31, 2021 at 8:17

Comments

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.