How to create a continuously running socket client in python

Question

I have been using TCP socket for a while now in python and my socket client closes after sending a message but I want to create a continuously running socket client that will keep sending messages as I already have a continuously running listener server. So the socket client code which I like to work on is below:

import socket
TCP_IP = "0.0.0.0"
TCP_PORT = 5003
BUFFER_SIZE = 1024
array = [0, 5, 10, 15]
print("Sending sensor value",array)
MESSAGE = bytearray(array) # converting to bytearray for sending via socket
# Sending via socket
s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
s.connect((TCP_IP,TCP_PORT))
s.send(MESSAGE)
data = s.recv(BUFFER_SIZE)
s.close()

please advise

• mkrieger1: Have you tried putting s.send and s.recv into a loop?
• wwii: while some_condition_exists: ... ?
• wwii: Did you see the examples at the end of the socket documentation??
• wwii: There are quite a few questions and answers on SO searching with your question. Do any of them answer your question? If so, let us know and we will mark yours as a duplicate.
• Farhan Kabir: @mkrieger1 yes I did. it workes but after some time my Linux freezes. That is why I was looking for all possible ways.

Answer 1

Try this:

import socket
import time
TCP_IP = "0.0.0.0"
TCP_PORT = 5003
BUFFER_SIZE = 1024
array = [0, 5, 10, 15]
MESSAGE = bytearray(array) # converting to bytearray for sending via socket
# Sending via socket
while True:
 s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
 s.connect((TCP_IP,TCP_PORT))
 s.send(MESSAGE)
 data = s.recv(BUFFER_SIZE)
 print("Sending sensor value",array)
 time.sleep(3)
 s.close()

• Farhan Kabir: Thanks a lot! Actually, I tried it just now and it is working. Didn't put any delay though before