With an array like the following, how can I filter objects based on the texts.id? For example if I wanted to return this very same array without the texts object reffering to the id 123 how would I go about it? I have access to the id I want to filter out and also the name of the object where its located. I have been trying to figure this out but I am not sure this is doable with the filter method only. Thanks in advance to anyone that helps.
[
0: Object {
name: 'Name 1',
texts[
0: Obj{
id: '123',
body: 'test message'
},
1: Obj{
id: '456',
body: 'test message 2'
}
]
},
1: Object {
name: 'Name 2',
texts[
0: Obj{
id: '789',
body: 'test message3'
},
1: Obj{
id: '101112',
body: 'test message 4'
}
]
}
]
2 Answers 2
It's not totally clear to me whether you want to remove the entire outer object where the texts array contains an object with a certain id (i.e: in your example, this would remove the whole object with name 'Name 1'), or if you just want to remove the object in the texts array which has a certain id (i.e: leaving the outer object, just removing the object in texts with id 123).
The former has been answered by @lissettdm above, but if it's the latter, you could do something like this:
const filter = "123";
entry.forEach(item => item.texts = item.texts.filter(text => text.id !== filter));
3 Comments
entry by whatever the name of the variable containing your multi-dimensional array of objects is.Yes, it is possible using Array.prototype.filter() and Array.prototype.find()
const entry = [{name: "Name 1",texts: [{id: "123",body: "test message"},{id: "456",body: "test message 2"}]},{name: "Name 2",texts: [{id: "789",body: "test message3"},{id: "101112",body: "test message 4"}]}];
const filter= "123";
const output = entry.filter(item => item.texts.find(text=> text.id===filter));
console.log(output);
Comments
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textsproperty of each member of the outer array.