1

I'm trying to use loop variable in executeSql function that contained by loop. But loop variable gets the last value if i don't use a closure. When i use a closure , i don't get the result list from executeSql function. Examples:

for (var i = 0; i < count; i++) {
tx.executeSql('SELECT AColumn FROM ATable WHERE refID=' + i, [],
function(tx,results) //success function
{
//do something
}
,errorfunction);
}

In success function "i" is always "count+1".

To solve this i changed my code like this:

for (var i = 0; i < count; i++) {
tx.executeSql('SELECT AColumn FROM ATable WHERE refID=' + i, [],
(function(tx,results) //success function
{
//do something
})(i)
,errorfunction);
}

With this, i get the "i" right. But "results" is undefined.

I tried to pass "tx" and "i" like this:

 (function(tx,results) //success function
 {
 //do something
 })(tx,null,i)

With this i understand why i get "results" as null. I want to learn how can i get the right results of executeSql.

asked Jun 27, 2011 at 12:04

1 Answer 1

3

You're looking for the following:

for (var i = 0; i < count; i++) {
 tx.executeSql('SELECT AColumn FROM ATable WHERE refID=' + i, [],
 (function(i){
 return function(tx,results) //success function
 {
 //do something
 };
 })(i),
 errorfunction);
}

At the end of the day you need to pass a function of the signature function(tx,res) which is clearly what that whole (function(i){ return function(tx,res){ ... }; })(i) does, since the outer anonymous function executes immediately and returns a function of that signature.

The value i in that inner function has the value of i when the outer function was called (i.e. the value of each iteration), since the value i is passed by value into the outer anonymous function, so references to i in the returned inner function will resolve correctly.

answered Jun 27, 2011 at 12:10
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1 Comment

not working for me. I have posted my question stackoverflow.com/questions/19313901/…

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