Python, working with lists

Question

I have such list of tuples:

lst = [(10, u'1.15', u'1.15'), (5, 0, u'1.875'), (3, u'2.28', u'2.28')]

and I want to get the new one with just second and third element of each tuple, which not equal to the 0, in other words, I need something like:

new_lst = [u'1.15', u'1.15',u'1.875', u'2.28', u'2.28']

Thanks for your answers.

Answer 1

new_lst = [x for t in lst for x in t[1:] if x != 0]

Answer 2

>>> [x for y in lst for x in y[1:3] if x]
[u'1.15', u'1.15', u'1.875', u'2.28', u'2.28']

Answer 3

>>> L = [(10, u'1.15', u'1.15'), (5, 0, u'1.875'), (3, u'2.28', u'2.28')]
>>> answer = []
>>> for tup in L:
... answer.extend([i for i in tup[1:] if i])
... 
>>> answer
[u'1.15', u'1.15', u'1.875', u'2.28', u'2.28']

Hope this helps

• Sven Marnach: Strange -- this looks like you typed it in the interactive interpreter, but you obviously didn't, since the result is incorrect. I'm really curious how this happened :)
• inspectorG4dget: This is exactly what the interpreter gives me. How do you suggest that this is wrong?
• Sven Marnach: For me, it gives [u'1.15', u'1.15', 0, u'1.875', u'2.28', u'2.28'].
• inspectorG4dget: @Sven: you're right. I had to do an oldschool copy-paste (read and rewrite), and had missed that one