Reverse array NOT using reverse

Question

I am looking for a way to get my array to create a new array, with numbers in reverse without using the reverse method.

e.g.

let numbers = [1, 2, 3]
console.log(reverse(numbers))

should return "[3, 2, 1]".

Thanks

• Jaromanda X: note: arrays have a reverse method
• Elanochecer: Why not using the .reserve() method?
• Yury Tarabanko: "I will use an for loop." ok, what is the question?
• Waqar Akram: Please try instead of reverse(numbers) this numbers.reverse()
• Ricardo Sanchez: const numbers = [1, 2, 3, 4, 5, 6]; const result = numbers.reduce((a, b) => [b].concat(a), []);

Answer 1

Here. A quick solution with map. returns you new array

let numbers = [1, 2, 3]
let result = numbers.map((el, i, arr) => arr[arr.length - 1 - i])
console.log(result)

Answer 2

Here is a quick way using a standard for loop

const numbers = [1, 2, 3]
const reverse = [];
for (let i = numbers.length - 1; i >= 0; i--) {
 reverse.push(numbers[i])
}
console.log(reverse);

Answer 3

Short and simple:

let numbers = [1, 2, 3, 4];
const reverse = (array) => array.map(array.pop, [...array]);
console.log(reverse(numbers));