Removing specific duplicates from an array Javascript

Question

I have an array like this

const ex = [
 {
 name: 'John',
 sender: "12345678",
 receiver: {
 name: "simi",
 age: 20,
 city: "New York"
 },
 time: 12:30 am
 },
 {
 name: 'Jane',
 sender: {
 name: "simi",
 age: 20,
 city: "New York"
 },
 receiver: "12345678",
 time: 1:00 pm
 }
]

In this array, the sender property value in the first object is equal to the receiver property value in the second object. Is there a way I can check and produce only one occurence of this value, that is, just one object in which the value is present

• EugenSunic: what does this value mean object value or property value?
• Similoluwa Odeyemi: property value.

Answer 1

Try this:

const ex = [
 {
 name: 'John',
 sender: "12345678",
 receiver: {
 name: "simi",
 age: 20,
 city: "New York"
 },
 time: "12:30 am"
 },
 {
 name: 'Jane',
 sender: {
 name: "simi",
 age: 20,
 city: "New York"
 },
 receiver: "12345678",
 time: "1:00 pm"
 }
]
let map = {}
ex.forEach(e => {
 let obj = null;
 if(e.sender instanceof Object) 
 obj = e.sender;
 else if(e.receiver instanceof Object) 
 obj = e.receiver;
 if(!obj) return;
 let key = obj.name+obj.age+obj.city;
 if(!map[key])
 map[key] = e;
});
console.log(Object.values(map));

• Similoluwa Odeyemi: Thanks for your response, what if I still want to have it in array. Lets say there's a possibility of have several scenarios like that
• Majed Badawi: @SimiloluwaOdeyemi Object.values(map) is another array containing the new unique elements.