create multiple folders in a directory

Question

I want to create multiple folders within themselves. If I have 3 folder I want to make on my desktop nested within each other. I want create the directory 'C:/Users/User/Desktop/folder_a/folder_b/folder_c/' the way I currently do this is I call os.path.exists() and os.mkdir() multiple times. Is there a way to do this without having to call these multiple times?

import os
DIR = 'C:/Users/User/Desktop/folder_a/folder_b/folder_c/'
if not os.path.exists(DIR):
 os.mkdir(DIR)
DIR = DIR + 'folder_b/'
if not os.path.exists(DIR):
 os.mkdir(DIR)
DIR = DIR + 'folder_c/'
if not os.path.exists(DIR):
 os.mkdir(DIR)

• Jab: Does this answer your question? How to create multiple nested folders in Python?

Answer 1

So we only need to do one check :) As folder_b can not exist if folder_a is not present.

Which brings us to the 2nd scenario. For which we leave out exist_ok=True for the appropriate check to be made again, but for the inclusion of folder_b and 'folder_c' if neither exist.

Option 1:

from os import (
 makedirs,
 path,
)
dir_path = 'C:/Users/User/Desktop/folder_a/{}'
if path.exists(dir_path):
 makedirs(
 dir_path.format(
 'folder_b/folder_c/',
 )
 )

Option 2:

from os import makedirs
dir_path = 'C:/Users/User/Desktop/folder_a/folder_b/folder_c'
makedirs(dir_path)

Answer 2

I wrote a recursive function for you:

import os
DIR = './folder_a/folder_b/folder_c/'
def make_nested_folders(DIR):
 print(DIR)
 if "/" in DIR:
 DIR, last = DIR.rsplit("/", 1)
 make_nested_folders(DIR)
 else:
 last = DIR
 if last and not os.path.exists(last):
 os.mkdir(last)
make_nested_folders(DIR)