How to check if array contain a value

Question

I am trying to create if condition with explicitly defined array:

So "standard" is:

public static void main(String[] args) {
 int[] number = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
 if(contains(number, 2)){
 System.out.println("Array contain number 2");
 }
}
public static boolean contains(final int[] array, final int v) {
 boolean result = false;
 for(int i : array){
 if(i == v){
 result = true;
 break;
 }
 }
 return result;
}

But how should I create something like this:

public static void main(String[] args) {
 
 if(contains({1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, 2)){
 System.out.println("Array contain number 2");
 }
}

Because I am getting an error Array initializer is not allowed here

• Eran: if(contains(new int[] {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, 2)){
• Lino: You could change the signature of contains to this: contains(int v, int... array) then you can call it like this: contains(2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

Answer 1

Already people have answered in comment section, But here I am showing you how you can do it in Java8, if you are looking for some fancy way like this :

boolean result = Arrays.stream(array).anyMatch(x->x==2) 

or By using IntStream.

boolean result = IntStream.of(array).anyMatch(x -> x == 2)