Removing value from array in JS

Question

Im new to software development and have been taking a class, im having an issue with finding out how to remove items in an array based on a 2nd argument character

Write a function "removeWordsWithChar" that takes 2 arguments:

1. an array of strings
2. a string of length 1 (ie: a single character) It should return a new array that has all of the items in the first argument except those that contain a character in the second argument (case-insensitive).

Examples:

----removeWordsWithChar(['aaa', 'bbb', 'ccc'], 'b') --> ['aaa', 'ccc']

----removeWordsWithChar(['pizza', 'beer', 'cheese'], 'E') --> ['pizza']

function removeWordsWithChar(arrString, stringLength) {
 const arr2 = [];
 for (let i = 0; i < arrString.length; i++) {
 const thisWord = arrString[i];
 if (thisWord.indexOf(stringLength) === -1) {
 arr2.push(thisWord);
 }
 }
return arr2;
}

• user120242: Array.prototype.filter arr2.filter(x=>!x.toLowerCase().includes(strLength.toLowerCase()))
• CascadiaJS: it should be case insensitive, so use if (thisWord.toLowerCase().indexOf(stringLength.toLowerCase()) === -1)
• adeel-justice: that worked! i cant believe i missed the lowercase. Thank you!
• user120242: you can also use localeCompare developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
• user120242: Does this answer your question? How to do case insensitive string comparison?

Answer 1

As they said in comments you can use filter like this:

function removeWordsWithChar(elems, string){
 return elems.filter(elem => !elem.toLowerCase().includes(string.toLowerCase()));
}