Checking for loop and if conditional, yet it doesn't print string

Question

For this code, I predicted that it would result in 'Rachel likes the languages 'Python', 'Javascript', 'HTML/CSS'' and 'ye', I got the first part but not the second part. Doesn't the code check each item in people list, and if that person is equal to the key of the fav_lang dictionary, it will print 'ye'?

fav_lang = {
 'Rachel':['Python','Javascript','HTML/CSS'],
}
for name, language in fav_lang.items():
 print(name, 'likes the languages', str(language).replace('[','',1).replace(']',''))
people = ['Rachel','Hannah','Safia','Ilda']
for peeps in people:
 if peeps == fav_lang.keys():
 print('ye')

gives the output:

Rachel likes the languages 'Python', 'Javascript', 'HTML/CSS'

• deadshot: change if peeps == fav_lang.keys(): to if peeps in fav_lang:

Answer 1

Change the following part:

for peeps in people:
 if peeps == fav_lang.keys():
 print('ye')

To:

for peeps in people:
 if peeps in fav_lang.keys():
 print('ye')

Because fav_lang.keys() returns a list.