Calling a class that is inside a function

Question

Would it be possible to call a class that is inside of a function?

Example:

def func():
 class testclass:
 print("testclass")

How would i call testclass in a position like this?

• azro: You can call it only from inside the method
• L3viathan: The class is redefined every time you call the function. You can't easily access the class from outside the function.
• Konrad Rudolph: You can’t "call" a class. in the code you’ve shown you’re defining a class, and when you create objects from it you are instantiating it.
• juanpa.arrivillaga: The same way you use any object created inside a function, you return it from the function and it is up to the caller to use the object.

Answer 1

def mymethod(value):
 class TestClass:
 def __init__(self, a):
 self.a = a
 t = TestClass(value)
 print(f"Inside method printing a value {t.a}")
 return t
test = mymethod(5)
print(f"Outside method printing object's value {test.a}")

Possible.

Answer 2

Of course you can do this; however python has several ways to build classes with different characteristics. Some strategies you may want to look into include inheritance or "mixins" and/or to have several constructor methods like in this answer: https://stackoverflow.com/a/682545/6019407

I think this approach is generally considered more in keeping with the python style ("pythonic").