I want to create an array in javascript and remember two ways of doing it so I just want to know what the fundamental differences are and if there is a performance difference in these two "styles"
var array_1 = new Array("fee","fie","foo","fum");
var array_2 = ['a','b','c'];
for (let i=0; i<array_1.length; i++){
console.log(array_1[i])
}
for (let i=0; i<array_2.length; i++){
console.log(array_2[i])
}
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I'm pretty sure they do the same thing.Seth– Seth2011年05月18日 15:58:55 +00:00Commented May 18, 2011 at 15:58
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Looks like a duplicate of stackoverflow.com/questions/931872/…Paul Butcher– Paul Butcher2011年05月18日 16:01:06 +00:00Commented May 18, 2011 at 16:01
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@seth I know they do the same thing but whats the difference is the question is there any performance gain / loss ?mcgrailm– mcgrailm2011年05月18日 16:01:36 +00:00Commented May 18, 2011 at 16:01
5 Answers 5
They do the same thing. Advantages to the [] notation are:
- It's shorter.
- If someone does something silly like redefine the
Arraysymbol, it still works. - There's no ambiguity when you only define a single entry, whereas when you write
new Array(3), if you're used to seeing entries listed in the constructor, you could easily misread that to mean[3], when in fact it creates a new array with alengthof 3 and no entries. - It may be a tiny little bit faster (depending on JavaScript implementation), because when you say
new Array, the interpreter has to go look up theArraysymbol, which means traversing all entries in the scope chain until it gets to the global object and finds it, whereas with[]it doesn't need to do that. The odds of that having any tangible real-world impact in normal use cases are low. Still, though...
So there are several good reasons to use [].
Advantages to new Array:
- You can set the initial length of the array, e.g.,
var a = new Array(3);
I haven't had any reason to do that in several years (not since learning that arrays aren't really arrays and there's no point trying to pre-allocate them). And if you really want to, you can always do this:
var a = [];
a.length = 3;
7 Comments
new Array(3) isn't exactly the same as [undefined, undefined, undefined]. In the latter case, the array has properties "0", "1" and "2", whereas in the former, the array does not have these properties. This is illustrated by the fact that ("0" in [undefined, undefined, undefined]) returns true while ("0" in new Array(3)) returns false.There's no difference in your usage.
The only real usage difference is passing an integer parameter to new Array() which will set an initial array length (which you can't do with the [] array-literal notation). But they create identical objects either way in your use case.
1 Comment
var ar = [5]; with the new Array syntax :)This benchmark on JSPerf shows the array literal form to be generally faster than the constructor on some browsers (and not slower on any).
This behavior is, of course, totally implementation dependent, so you'll need to run your own test on your own target platforms.
3 Comments
I believe the performance benefits are negligible.
Comments
I think both ways are the same in terms of performance since they both create an "Array object" eventually. So once you start accessing the array the mechanism will be the same. I not too sure about how different the mechanisms to construct the arrays be (in terms of performance) though it shouldn't be any noticeable gains using one way to the other.