For loop execution in Python

Question

I am new to python and just in the initial phase of the basics. Can someone please explain me how the for loop in the below code works? and I really don't get how number 9 is getting 3 as inner value.

Kindly tell me how the loops executes. TIA.

CODE:

for outer in range(2,10):
 for inner in range(2,outer):
 if not outer%inner:
 print(outer,'=',inner,'*',int(outer/inner))
 break 
 else:
 print(outer,'is prime')

---

Output:
2 is prime
3 is prime
4 = 2 * 2
5 is prime
6 = 2 * 3
7 is prime
8 = 2 * 4
9 = 3 * 3

Answer 1

The inner loop runs multiple times for each execution of outer loop.

For value of 9 of outer loop, the inner loop executes from 2 to outer value.

Answer 2

I commented your code below, It should explain what is going on.

# This loop loops through numbers 2-9, and assigns them to the variable 'outer'
for outer in range(2,10):
 # This loop loops through numbers 2-(outer-1), and assigns them to the variable 'inner'
 for inner in range(2,outer):
 # if outer % inner == 0, the code is executed
 if not outer%inner:
 # When this is executed for 9, it will print 9 = 3 * 3
 print(outer,'=',inner,'*',int(outer/inner))
 break 
 else:
 print(outer,'is prime')

• marxmacher: first comment loops through 2-9 and assigns them to variable would be correct

Answer 3

Your inner loop executes multiple times for every one execution of the outer loop.

For an outer value of 9 your inner loop will execute from 2 to (outer) which is 9.