how to pass object's function name as a parameter

Question

What I am trying to do is something like this:

def custom_logger(user_logger, log_level, *args, **kwargs): 
 # do some stuff..
 user_logger.log_level(*args, **kwargs)

or like this:

def create_logger(module_name, log_level=DEBUG):
 logger = logging.getLogger(module_name)
 logger.setLevel(logging.log_level)

How can I achieve something like this? Because it will clean up a lot of things.

• jknotek: You are mostly correct, but kwargs should have 2 asterisks: **kwargs.
• John Gordon: Is your question how to pass the function name in the caller, or how to use the function name in the callee?
• Eziz Durdyyev: @jknotek, are you telling me that this code will work?
• jknotek: @EzizDurdyyev Well, conceptually, yes, it will work. But I don't know anything about how your logger is implemented. So you'll have to try it yourself and debug as needed.
• John Gordon: As written, I don't believe this code will work, because it will call literally user_logger.log_level() instead of using whatever function name was passed as the log_level argument.

Answer 1

You can use the getattr function to obtain an attribute by name:

def custom_logger(user_logger, log_level, *args, **kwargs): 
 log = getattr(user_logger, log_level) # or log_level.lower() if log_level is in upper case
 # do some stuff..
 log(*args, **kwargs)
def create_logger(module_name, log_level=DEBUG):
 logger = logging.getLogger(module_name)
 logger.setLevel(getattr(logging, log_level))

• Eziz Durdyyev: how can I apply this to create_logger?
• Eziz Durdyyev: @blhsubg, did you try it before you answered, or you sure this will work with loggers? again, may be i am doing it wrong but.. it won't work with me. sorry