get list of object from array of objects using javascript

Question

It is a simple javascript problem and i am unable to get my head through it

const jsObjects = [
 {a: 1, b: 2}, 
 {a: 3, b: 4}, 
 {a: 5, b: 6}, 
 {a: 7, b: 8}
 ]
let result = jsObjects.find(obj => {
 return obj.b === 6
})
console.log(result)

i just want to console the entire list of 'b' rather than find a single variable 'b' which holds value 6

is there any way to do that

• Amir Popovich: jsObjects.filter(obj => obj.b === 6);
• arizafar: let out = jsObjects.map(e => e.b)

Answer 1

You can use Array.filter() instead of Array.find()

const jsObjects = [
 {a: 1, b: 2}, 
 {a: 3, b: 4}, 
 {a: 5, b: 6}, 
 {a: 7, b: 8}
 ]
 
 
let result = jsObjects.filter(obj => obj.b === 6)
console.log(result)

UPDATE

If you want to take only one property, then you can use Array.map()

const jsObjects = [
 {a: 1, b: 2}, 
 {a: 3, b: 4}, 
 {a: 5, b: 6}, 
 {a: 7, b: 8}
 ]
 
 
let result = jsObjects.map(obj => obj.b)
console.log(result);

• juhi: i need the output like this: {b: 2, b:4, b:6, b:8} how can i get this?
• Harun Yilmaz: Your desired output is not a valid object structure as it holds different values for same key. If you need to get them as array, please see updated answer

Answer 2

If you still want them as objects in an array, you can update Harun's code like this:

let myBs = [];
let result = jsObjects.map(obj => myBs.push({b: obj.b}));
console.log(myBs);```