While loop not looping - Python

Question

A while loop in my code is not looping.

I've tried ensuring the while loop would loop but no loop was executed.

#Name_Input
login = 1
while login == 1:
 print("Enter the username and password \n")
 username = input("Username: ")
 password = input("Password: ")
 if password and username != "cameron" and "123":
 print("\nWrong username or password... \nTry Again...")
 login = 1

I am expecting the loop to go back to the login when the login details are entered incorrectly.

• Some programmer dude: The condition in your if doesn't work as you expect. You need to do something like if condition_1 or condition_2
• Haukland: Why not use boolean value for login?
• bruno desthuilliers: @owninggreendragsdude because 1 is a boolean value. Actually all objects in Python have a boolean value, the bool type was a later (and highly debated FWIW) addition.
• bruno desthuilliers: @owninggreendragsdude also the OP may have a need for more than possible 2 values here (I fail to imagine why but we only have a short excerpt of the real code) ;-)

Answer 1

login = 1
while login == 1:
 print("Enter the username and password \n")
 username = str(input("Username: "))
 password = str(input("Password: "))
 if username == "cameron" and password == "123":
 login=2
 else:
 print("\nWrong username or password... \nTry Again...")

Answer 2

Try this if syntax:

login = 1
while login == 1:
 print("Enter the username and password \n")
 username = input("Username: ")
 password = input("Password: ")
 if password != "123" or username != "cameron":
 print("\nWrong username or password... \nTry Again...")
 login = 1
 else:
 login = -1

• Some programmer dude: The condition still won't work as the OP expects (I believe). Please read up on De Morgan's laws. And read the message being printed, it contains the right logic. :)