Remove duplicates from Array string

Question

It's really childish to ask this question but really want an optimal solution for this. I have an array of string

("a1,a2", "a3,a4", "a2,a1", "a5,a3")

and I want to Display

("a1,a2", "a3,a4", "a5,a3")

i.e. the first string is in, its duplicates are omitted.

Note: the order of the elements must be preserved

• AnsFourtyTwo: Also this is a tuple, not an array.
• Umair Ayub: Possible duplicate of Remove duplicates in a list while keeping its order (Python)

Answer 1

This is one approach.

Ex:

data = ("a1,a2","a3,a4","a2,a1","a5,a3") 
seen = set()
result = []
for i in data:
 if ",".join(sorted(i.split(","))) not in seen:
 result.append(i)
 seen.add(i) 
print(result)

Output:

['a1,a2', 'a3,a4', 'a5,a3']

• Pynchia: the inner list (the one inside set) is unnecessary
• Sharath Nayak: I forgot to add about the "order" in the question. Actually order is required. Thank you for the answer. will try the answer.
• Rakesh: @SharathNayak. Updated snippet

Answer 2

your data is in a variable called "data".

new_data = []
for example in data:
 example2 = str(example.split(",")[1] + "," + example.split(",")[0])
 if example in new_data or example2 in new_data:
 continue 
 else:
 new_data.append(example) 
print(new_data) 

If you want to store them in your original list, run this script.

data.clear()
data = new_data.copy()