How to parse this nested dictionary datastructure in Python 3?

Question

I have a dictionary (named dict1) that has the following structure:

dict1 = {
 'Classroom': [{
 'Subject': "Calculus",
 'Students': [
 {'Name': "Joe", 'Age': 12, 'Weight': 126, 'Gender': "Male"},
 {'Name': "Doug", 'Age': 13, 'Weight': 95, 'Gender': "Male"},
 {'Name': ..., 'Age': ..., 'Weight': ..., 'Gender': ...}
 ]
 }]
}

The list (which contains name, age, weight, and gender) within this dictionary is very long, and I wanted to parse the Name, Age, and Gender out, and append them onto another list like this:

mylist = [("Joe", 12, "Male"), ("Doug", 13, "Male"), ... ]

I tried seraching online and tinkered around with code such as this:

mylist = []
dict2 = dict1['Classroom'][0]['Students'][0]['Name']
mylist.append(dict2)

But what happens is that it only appends the first name (Joe). Furthermore, I'm not sure how to parse three items (name, age, and gender) at the same time. Does anyone have a way to do this without having to use libraries?

• Ṃųỻịgǻňạcểơửṩ: Where is the original dict file?
• F16Falcon: @Ṁữl·lɪgắnậcễơưṩᛗ Apologies, I updated it. The original dict is the first dictionary that I wrote on my post.
• Ṃųỻịgǻňạcểơửṩ: The dictionary 'dict' consists of just one parent key and the value is a list.
• F16Falcon: @Ṁữl·lɪgắnậcễơưṩᛗ Correct, but there are dictionaries within that list, which is why I tried doing the "dict['classoom'][0]" thing to specify what items in the lists I want. But it only prints one name for some reason...

Answer 1

Your dict1 contains one key, 'Classroom' whose value is a list with one entry. That entry, is also a dict which contains two keys. You want the 'Students' key as that contains the list of all the students. It is a list. Iterate through that list and group the fields into a tuple.

It is technically a list ['Students'] nested within a dictionary ['Classroom'][0] within a list ['Classroom'] within a dictionary dict.

The code will be

mylist = []
studentlist = dict1['Classroom'][0]['Students']
for s in studentlist:
 m = (s['Name'], s['Age'], s['Gender'])
 mylist.append(m)

For the test case

classroom = {'Classroom': 
 [{'Subject': "Calculus", 'Students': 
 [
 {'Name': "Joe", 'Age': 12, 'Weight': 126, 'Gender': "Male"}, 
 {'Name': "Doug", 'Age': 13, 'Weight': 95, 'Gender': "Male"},
 {'Name': "Omg", 'Age': 50, 'Weight': 99, 'Gender': "Female"}
 ]
 }]
}

you will end up with

[('Joe', 12, 'Male'), ('Doug', 13, 'Male'), ('Omg', 50, 'Female')]

• F16Falcon: This works, thanks! I was also just now thinking of using "for s in studentlist", so good to know that I'm learning! :)

Answer 2

student_list = []
classroom_list = dict1['Classroom']
# this is the first iteration list
for classroom in classroom_list:
 student_list = classroom['Students']
 # this is the second iteration list
 for student in student_list:
 student_list.append(student['Name'], student['Age'], student['Gender'])
#student_list = [("Joe", 12, "Male"), ("Doug", 13, "Male"), ... ]