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hello what is the php equivalent of the following javascript code?

function arePointsNear(checkPoint, centerPoint, km) {
 var ky = 40000 / 360;
 var kx = Math.cos(Math.PI * centerPoint.lat / 180.0) * ky;
 var dx = Math.abs(centerPoint.lng - checkPoint.lng) * kx;
 var dy = Math.abs(centerPoint.lat - checkPoint.lat) * ky;
 return Math.sqrt(dx * dx + dy * dy) <= km;
}
var vasteras = { lat: 41.235188, lng: 28.495035 };
var stockholm = { lat: 41.09774752058191, lng: 29.080487759810946 };
var n = arePointsNear(vasteras, stockholm, 49);
console.log(n);
marv255
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asked Jun 25, 2019 at 21:58
1
  • abs(-4.2); for Math.abs. cos(M_PI); for Math.cos, sqrt(9); for Math.sqrt. php.net/manual/en/function.sqrt.php All searchable here. Commented Jun 25, 2019 at 22:02

1 Answer 1

3
function arePointsNear($checkPoint, $centerPoint, $km) {
 $ky = 40000 / 360;
 $kx = cos(pi() * $centerPoint['lat'] / 180.0) * $ky;
 $dx = abs($centerPoint['lng'] - $checkPoint['lng']) * $kx;
 $dy = abs($centerPoint['lat'] - $checkPoint['lat']) * $ky;
 return sqrt($dx * $dx + $dy * $dy) <= $km;
}
$vasteras = ['lat' => 41.235188, 'lng' => 28.495035];
$stockholm = ['lat' => 41.09774752058191, 'lng' => 29.080487759810946];
$n = arePointsNear($vasteras, $stockholm, 49);
var_dump($n);

But specialised solutions like https://github.com/mjaschen/phpgeo is preferable.

answered Jun 25, 2019 at 22:05
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