Initialising an array using different array

Question

I have a code that goes as:-

.....
path = 'path_to_csv_file';
file=open(path, "r")
reader = csv.reader(file)
y=np.empty((7000,1))
j=0
for line in reader:
 y[j]=line[0]
 j+=1
....
targets=np.zeros([7000,1,10])

Now, in the first array of targets, I want the y[0]th index to store 1 (y[0] stores integers from 0-9). For that, I wrote:-

targets[0,0,y[0]]=1

But I get an error:-

IndexError: arrays used as indices must be of integer (or boolean) type

When I print y[0], I get:-

[6.]

as the output. What I think is that it's not an integer, so that's probably the source of my error, but I don't know how to fix it. Any help will be appreciated. Thanks!

• Karls: Use print(y[0]) and show us results. In general there's nothing wrong in targets=np.zeros([7000,1,10]) and targets[0,0,y[0]]=1. Just hardcode y[0] to try (for example y=[[1,2,3,4,5],[1,2,3,4,5]]). The most likely the error is in reading y from file.
• Ankit Kumar: @Karls I've already shown the result for print(y[0]). It gives me [6.]
• Karls: Ah ok, I see. And what is the content of your csv file?
• Ankit Kumar: @Karls It goes like 6,0,0,0....... The answer below works by the way, thanks!

Answer 1

Have you tried with dtype=int?

y=np.empty((7000,1), dtype=int)
...
targets=np.zeros(([7000,1,10]), dtype=int)

You can check more on the documentation on the usage of numpty.empty and numpty.zeros

• denis_lor: @AnkitKumar In case it helped, mark the answer as accepted so anyone else with the same question can understand the answer worked out
• Ankit Kumar: Ya, there's a time limit before which i can't accept it, I was just waiting for that