I have a byte array which I'm encrypting then converting to a string so it can be transmitted. When I receive the string I then have to convert the string back into a byte array so it can be decrypted. I have checked that the received string matches the sent string (including length) but when I use something like str.getBytes() to convert it to a byte array, it does not match my original byte array.
example output:
SENT: WzShnf/fOV3NZO2nqnOXZbM1lNwVpcq3qxmXiiv6M5xqC1A3
SENT STR: [B@3e4a9a7d
RECEIVED STR: [B@3e4a9a7d
RECEIVED: W0JAM2U0YTlhN2Q=
any ideas how i can convert the received string to a byte array which matches the sent byte array?
Thanks
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3For converting String to Byte Array use this : String stringToConvert = "This String is 76 characters long and will be converted to an array of bytes"; byte[] theByteArray = stringToConvert.getBytes();Kartik Domadiya– Kartik Domadiya2011年03月31日 12:39:15 +00:00Commented Mar 31, 2011 at 12:39
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1W0JAM2U0YTlhN2Q= is Base64 for [B@3e4a9a7d, which looks like a String representation for a byte array in Java. If you are performing byte manipulation yourself, double check it as you may be sending the wrong data.mdrg– mdrg2011年03月31日 12:41:41 +00:00Commented Mar 31, 2011 at 12:41
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out is my byte array and when printed gives the first line of my example output. out.toString() definitely gives me [B@3e4a9a7dMitch– Mitch2011年03月31日 12:57:41 +00:00Commented Mar 31, 2011 at 12:57
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it would be helpful to see the code (part)user85421– user854212011年03月31日 13:29:52 +00:00Commented Mar 31, 2011 at 13:29
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stackoverflow.com/questions/17577887/…Sparrow_ua– Sparrow_ua2013年07月10日 22:45:37 +00:00Commented Jul 10, 2013 at 22:45
4 Answers 4
You used array.toString()
, which is implemented like this:
return "[B@" + Integer.toString(this.hashCode(), 16);
(In fact it inherits the definition from Object, and the part before the @
simply is the result of getClass().getName()
.)
And the hashCode here does not depend on the content.
Instead, use new String(array, encoding).
Of course, this only works for byte-arrays which are really representable as Java strings (which then contain readable characters), not for arbitrary arrays. There better use base64 like Bozho recommended (but make sure to use it on both sides of the channel).
1 Comment
This looks like Base64. Take a look at commons-codec Base64
class.
3 Comments
string.getBytes("ISO-8859-1")
, and then passing that as constructor arugment as well.sun.*
packages. They are proprietary API and may be removed at any time. Use any other public implementation, like the one suggested by Bozho.You can't just use getBytes() on two different machines, since getBytes uses the plattform's default charset.
Decode and encode the array with a specified charset (i.e. UTF-8) to make sure you get the correct results.
Comments
First do convertion of your byte array to proper string, by doing
String line= new String(Arrays.toString(your_array))
Then send it and use function below
public static byte[] StringToByteArray(String line)
{
String some=line.substring(1, line.length()-1);
int element_counter=1;
for(int i=0; i<some.length(); i++)
{
if (some.substring(i, i+1).equals(","))
{
element_counter++;
}
}
int [] comas =new int[element_counter-1];
byte [] a=new byte[element_counter];
if (a.length==1)
{
a[0]= Byte.parseByte(some.substring(0));
}
else
{
int j=0;
for (int i = 0; i < some.length(); i++)
{
if (some.substring(i, i+1).equals(","))
{
comas[j]=i;
j++;
}
}
for (int i=0; i<element_counter; i++)
{
if(i==0)
{
a[i]=Byte.parseByte(some.substring(0, comas[i]));
}
else if (i==element_counter-1)
{
a[i]=Byte.parseByte(some.substring(comas[comas.length-1]+2));
}
else
{
a[i]=Byte.parseByte(some.substring(comas[i-1]+2, comas[i]));
}
}
}
return a;
}