command execute directory

Question

i have to execute a command use python subprocess .

by default , command is execute as working on the directory where the python script file is . such as

 subprocess.Popen(shlex.split("ls -l"))

will list the file in the directory of the script file where is .

but i want this command to execute in another directory ,say , B . how can i do it .

i try this , but faild:

env['PWD'] = "/data/a"
f = tempfile.TemporaryFile('w+b')
p = subprocess.Popen(shlex.split(cmd),stdout= f,stderr=f,env=env)

Answer 1

You can use os.chdir or you use the cwd parameter to Popen.

Answer 2

ls -l list all items in current directory default. You could tell command ls -l which directory to list by using ls -l /your-path

Answer 3

hi did u try changing the unix command

ls -l 

to something like

ls -l /usr/share;

• mike: no , indeed i'm use execute the ls command , it's git command ,which can't put a path parameter.
• Anuj: can you say which command it is .. or use ; to combine two commands for eg: cd /var;ls