How to find a word(string) in Javascript array?

Question

I need to check if my array has the word

This is my code please help

 var name = ['heine', 'hans'];
 var password = ['12343', '1234'];
 function login() {
 var pos;
 if(name.includes('hans')) {
 console.log("enthält");
 pos = name.indexOf('hans');
 console.log(pos)
 if(password[pos] === '1234') {
 console.log("angemeldet")
 }
 }
 }

consoleout = 6, but why, it must be a 1

If the word hans is in the array, than i need the position from the word in the array

• Taplar: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
• Taplar: Terrible idea, in relation to authentication on the frontend, but from a mental exercise standpoint, you are asking about indexOf()
• Taplar: password[i] === 1234 will however always be false, due to the passwords being strings and the usage of ===
• Taplar: It is returning 6 because apparently it's thinking name is a string. Which is very odd.

Answer 1

You might find some() handy for this. It will pass the index into the callback which you can use to find the corresponding value from the passwords array:

function test(name, pw) {
 let names = ["heine", "hans"];
 let passwords = ["12343", "1234"];
 // is there `some` name/pw combinations that matches?
 return names.some((n, index) => name == n && pw == passwords[index])
}
console.log(test("hans", '1234')) // true
console.log(test("hans", '12345')) // false
console.log(test("hans", '12343')) // false
console.log(test("heine", '12343')) // true
console.log(test("mark", '12343')) // false
 

Answer 2

Problem here is name is window.name which is a string..

var name = ['heine', 'hans'];
console.log(window.name, typeof window.name)
var xname = ['heine', 'hans'];
console.log(window.xname, typeof window.xname)

Change your variable to another word that is not reserved if you are in global scope.

Answer 3

In your case, you can also try something like this with findIndex:

const usernames = ['heine', 'hans'];
const passwords = ['12343', '1234'];
function login(user, pass)
{
 let userIdx = usernames.findIndex(x => x === user);
 // On a real application do not give any tip about which is
 // wrong, just return "invalid username or password" on both cases.
 
 if (userIdx < 0)
 return "Invalid username!";
 if (pass !== passwords[userIdx])
 return "Invalid password!";
 return "Login OK!"
}
console.log(login("heine", "12343"));
console.log(login("hans", "lala"));

Answer 4

You may use this. I am not sure if it is what you want.

let names = ["heine", "hans"];
let password = ["12343", "1234"];
let i, temp;
function log(login, pass) {
 if((i = names.indexOf(login)) !== -1){
 if(password[i] === pass)
 console.log("Logged!");
 }
}
log("hans", "1234")

• Marvin Würtz: i think it need a for-loop, i just add it now an test it
• Marvin Würtz: code var name = ["heine", "hans"]; var password = ["12343", "1234"]; var i, temp; function login(login, pass) { console.log("start") for(temp = 0; temp < name.length; temp++) { console.log(temp) if((i = name.indexOf(login)) !== -1){ console.log("name") if(password[temp] === pass) console.log("Logged!"); } } } login("hans", "1234")