How to iterate over a list in if conditionals?

Question

Trying to iterate over range of numbers (or list) to check if values are equal. Seems very simple, but I cant seem to find a way to do it.

I am trying to use an if statement to check scope of items in a 2D array.

# check if x is equal to var if added to any number between 0 and 10.
if var == x + any(range(10)): # not how it works, but how I want it to
 # do something 

After looking into any() I realize that It just returns True if any item in the iterate is True

• Blckknght: I know it's not probably what you want, but for the specific example you give in the question, you could just use chained inequalities 0 <= var - x < 10. Also note that 10 is not included in range(10), so I use < 10 instead of <= 10 which would better match what you say you wanted to do. You may want to use range(11) in the answers below if 10 should be included in the tests.

Answer 1

Use any this way, also use generator:

if any(var==(x+i) for i in range(10)):
 # do something

• U13-Forward: @Retrnon Happy to help, :-), 😊😊😊

Answer 2

You have to use several Python functions for that:

if var in list(map(lambda item: x+item, range(10)))

list: Casts the parameter into a list object.

map: Applies a function (first parameter) to a collection of values (second parameter).

lambda: Lambda function.

Answer 3

You can also use this non-any version:

for i in range(10):
 if var == (x+i):
 break

Answer 4

Another way to do it using numpy:

import numpy as np
if var in x + np.arange(10) :
 # do something

Would suffer from floating point problem if your numbers are not integers.