Value is returned as None from function

Question

I am trying to get the value of an user input defined key from nested dictionary. While I am able to print out the value from the function itself. Return statement sends value as None.

people = {1: {'name': 'John', 'age': '27', 'sex': 'Male'},
 2: {'name': 'Marie', 'age': '22', 'sex': 'Female'},
 3: 'James',
 4: 'lance',
 'change1': {5: 'place'},
 'country': {'Waterloo': 'Waterloo', 'Australia': 'Australia'},
 6: {'Position': 'GM'}
 }
def getfromdict(mydict, mykey):
 for i in mydict.keys():
 if type(mydict[i])==dict:
 newdict = mydict[i]
 getfromdict(newdict, mykey)
 elif i == mykey:
 print(mydict[i])
 valuefound = mydict[i]
 return valuefound
 else:
 continue
result = getfromdict(people,5)
print(result)

• vicky_loves_to_code: This is the output of code execution: --> place None Process finished with exit code 0
• Sunder R: have you tried my answer

Answer 1

Line three of your code snippet should read

 return getfromdict(newdict, mykey)

To find a leaf in a tree, well, you can, for istance,

def leaf(tree, key):
 if key in tree: return tree[key]
 for subtree in filter(lambda s: isinstance(s, dict), tree.values()):
 ret_val = leaf(subtree, key)
 if ret_val is not None: return ret_val

This implementation has the property that if a key is found at some level, whatever it points to is returned, either a leaf or a subtree (in undesired, a fix is quite straightforward).

• Sunder R: have you tried running the code, it won't work as it will get excited in the first nested loop itself

Answer 2

You can try this to search the keys in the nested JSON

 def getfromdict(mydict, mykey):
 if type(mydict) == type({}):
 for k1 in mydict:
 if k1 == mykey:
 return mydict[k1]
 fromdict = getfromdict(mydict[k1], mykey)
 if fromdict is not None:
 return fromdict

• Sunder R: can you mark this solution as answered, because the other solution is misleading is misleading