python function output None

Question

import random
def getAnswer (answerNumber):
 if getAnswer == 1:
 return 'It is certain'
 elif getAnswer == 2:
 return 'It is decidedly so' 
 elif getAnswer == 3:
 return 'Yes' 
 elif getAnswer == 4:
 return "Reply hazy try again"
 elif getAnswer == 5:
 return 'Ask again later'
 elif getAnswer == 6:
 return "Concentrate and ask again"
 elif getAnswer == 7:
 return 'My reply is no'
 elif getAnswer == 8:
 return 'not so good'
 elif getAnswer == 9:
 return 'doubtful'
r = random.randint(1 , 9)
future = getAnswer(r)
print(future)

• Johan Snowgoose: Add "print(answerNumber)" to the end of getAnswer, that will tell you what you've passed in. But really you need to check the code, you are checking getAnswer when I believe you want answerNumber in the if logic.
• user10844642: I didn't realize i was typing getAnswer in the if logic thank you!

Answer 1

You're passing in the random number as answerNumber and then checking against the value of getAnswer. So, the function is trying to compare a reference to a function with an integer, which will obviously never evaluate to True. Because none of the if statements evaluate to True, it gets to the end of your function without hitting a return statement, and so by default returns None.

Replace all of the getAnswer references in the function body with answerNumber and you should be all set. Something like:

import random
def getAnswer(answerNumber):
 if answerNumber == 1:
 return 'It is certain'
 elif answerNumber == 2:
 return 'It is decidedly so' 
 elif answerNumber == 3:
 return 'Yes' 
 elif answerNumber == 4:
 return "Reply hazy try again"
 elif answerNumber == 5:
 return 'Ask again later'
 elif answerNumber == 6:
 return "Concentrate and ask again"
 elif answerNumber == 7:
 return 'My reply is no'
 elif answerNumber == 8:
 return 'not so good'
 elif answerNumber == 9:
 return 'doubtful'
r = random.randint(1 , 9)
future = getAnswer(r)
print(future)

Answer 2

import random
def getAnswer (answerNumber):
 if answerNumber == 1:
 return 'It is certain'
 elif answerNumber == 2:
 return 'It is decidedly so' 
 elif answerNumber == 3:
 return 'Yes' 
 elif answerNumber == 4:
 return "Reply hazy try again"
 elif answerNumber == 5:
 return 'Ask again later'
 elif answerNumber == 6:
 return "Concentrate and ask again"
 elif answerNumber == 7:
 return 'My reply is no'
 elif answerNumber == 8:
 return 'not so good'
 elif answerNumber == 9:
 return 'doubtful'
r = random.randint(1 , 9)
future = getAnswer(r)
print(future)

you were comparing the function getAnswer to the integer value and since no else statement defined there, function call return None.

all i changed was to compare the actual number answerNumber to the number in code.