I have two python scripts that use two different cameras for a project I am working on and I am trying to run them both inside a different script or within each other, either way is fine.
import os
os.system('python 1.py')
os.system('python 2.py')
My problem however is that they don't run at the same time, I have to quit the first one for the next to open. I also tried doing it with bash as well with the & shell operator
python 1.py &
python 2.py &
And this does in fact make them both run however the issue is that they both run endlessly in the background and I need to close them rather easily. Any suggestion what I can do to avoid the issues with these implementations
3 Answers 3
You could do it with multiprocessing
import os
import time
import psutil
from multiprocessing import Process
def run_program(cmd):
# Function that processes will run
os.system(cmd)
# Initiating Processes with desired arguments
program1 = Process(target=run_program, args=('python 1.py',))
program2 = Process(target=run_program, args=('python 2.py',))
# Start our processes simultaneously
program1.start()
program2.start()
def kill(proc_pid):
process = psutil.Process(proc_pid)
for proc in process.children(recursive=True):
proc.kill()
process.kill()
# Wait 5 seconds and kill first program
time.sleep(5)
kill(program1.pid)
program1.join()
# Wait another 1 second and kill second program
time.sleep(1)
kill(program2.pid)
program2.join()
# Print current status of our programs
print('1.py alive status: {}'.format(program1.is_alive()))
print('2.py alive status: {}'.format(program2.is_alive()))
5 Comments
terminate() function and keep join() that will wait for processes to finish.One possible method is to use systemd to control your process (i.e. treat them as daemons).
This is how I control my Python servers since they need to run in the background and be completely detached from the current tty so I can exit my connection to the machine and the continue processes continue. You can then also stop the server later using systemctl, as explained below.
Instructions:
Create a .service file and save it in /etc/systemd/system, with contents along the lines of:
[Unit]
Description=daemon one
[Service]
ExecStart=/path/to/1.py
and repeat with one going to 2.py.
Then you can use systemctl to control your daemons.
First reload all config files with:
systemctl daemon-reload
then start either of your daemons (where my_daemon.service is one of your unit files):
systemctl start my_daemon
it should now be running and you should find it in:
systemctl list-units
You can also check its status with:
systemctl status my_daemon
and stop/restart them with:
systemctl stop|restart my_daemon
Comments
Use subprocess.Popen. This will create a child process and return its pid.
pid = Popen("python 1.py").pid
And then check out these functions for communicating with the child process and checking if it is still running.
python1.pyobviously python will never go to execute the next statement that in your case is another endless programpython2.py. For solving this you need to create two new process like when forking a child (Look on processes concepts) and communicate with the in some way.