I'm using javascript, and I have an array containing multiple values, which may be non-unique. I'd like to take this array and generate a new array, or ordered list, of its keys in ascending order of value. For example, if I have [ 2, 2, 4, 5, 1, 6 ], I'd like to generate [ 5, 4, 0, 1, 2, 3 ].
I was thinking of iterating over the original list and inserting each value into the new list while checking for proper placement by comparing to the existing values of the new list every time an insertion is performed. This seems wasteful, though, as I'd have to (potentially) check every value of the new list for every insertion.
Anyone have a simpler method for this?
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How does [5,4,0,1,2,3] follow from [2,2,4,5,1,6]?Alex– Alex2016年12月13日 02:51:36 +00:00Commented Dec 13, 2016 at 2:51
2 Answers 2
I think you meant [ 4, 0, 1, 2, 3, 5 ].
function GetSortedKeys(values) {
var array_with_keys = [];
for (var i = 0; i < values.length; i++) {
array_with_keys.push({ key: i, value: values[i] });
}
array_with_keys.sort(function(a, b) {
if (a.value < b.value) { return -1; }
if (a.value > b.value) { return 1; }
return 0;
});
var keys = [];
for (var i = 0; i < array_with_keys.length; i++) {
keys.push(array_with_keys[i].key);
}
return keys;
}
var array = [2, 2, 4, 5, 1, 6];
alert(GetSortedKeys(array));
This is the simplest method I can come up with on Javascript, unfortunately.
5 Comments
Using the nice Underscore.JS:
var get_sorted_keys = function(values) {
var keys_idx = [], i;
for (i = 0; i < values.length; i++) {
keys_idx.push(i);
}
var keys = _.sortBy(keys_idx, function(idx){ return values[idx]; });
return keys;
};
var array = [2, 2, 4, 5, 1, 6];
console.log("Sorted keys:", get_sorted_keys(array));
Output:
Sorted keys: [4, 0, 1, 2, 3, 5]