How to run a command line script in Python

Question

If I have a command line like this:

abc -c config.json| xyz -c test.json

How can I run it in Python file? I mean we will don't type "abc -c config.json| xyz -c test.json" in the terminal. xyz and abc are applications that I have written.

So, May I have a help?

Answer 1

You can use this

os.system("abc -c config.json| xyz -c test.json")

This is like running abc -c config.json| xyz -c test.json in command prompt.

Answer 2

Im a little confused by your question.

If you want to make a system call from within python you would use the subprocess module

x = subprocess.Popen("ls /home", shell=True, stdout=subprocess.PIPE).stdout.read()

If you want to run a python command from the command line you can either write it to a file and execute

python myFile.py

Or, run the commands directly to python

python -c "print("testing")"

• Han Van Pham: Sorry, I just updated my question. Yes, I know subprocess, but how can I run the with the command line like this: abc -c config.json| xyz -c test.json.
• Han Van Pham: I tried: subprocess.Popen(shlex.split("abc -c config.json| xyz -c test.json"), stdin=subprocess.PIPE, stdout=subprocess.PIPE) But It's not work for me.
• samson4649: what is "abc" and what is "xyz"? are these applications that you have written?
• Han Van Pham: Yes, these are applications that I have written, @samson4649.
• samson4649: why are you using "shlex.split() ? you should be able to run -> subprocess.Popen( "abc -c config.json| xyz -c test.json", stdin=subprocess.PIPE, stdout=subprocess.PIPE)